Question

Find the probability of randomly rolling 2 standard dice and having a sum that is EVEN or GREATER THAN 9.

Answer 1

Answer:

The answer is 5/9. Just took the quiz. Hope this helps. :)

Step-by-step explanation:

Answer 2

Answer:   $c.\ \dfrac{5}{9}$

Step-by-step explanation:

The total number of outcomes of rolling a die =6

Then , the total number of outcomes of rolling  two dice = 6 x 6 = 36

Now , Pairs of outcomes having a sum that is EVEN = (1,1), (2,2), (3,3) , (4,4), (5,5), (6,6) , (1,3), (1,5), (2,4), (2,6), (3,1), (3,5), (4,2), (2,6),(5,3), (5,1), (6,4), (6,2)

i.e. Number of outcomes having a sum that is EVEN  = 18

Pairs of outcomes having a sum that is GREATER THAN 9 =  (4,6), (6,4), (5,5), (5,6), (6,5), (6,6)

i.e. Number of outcomes having a sum that is GREATER THAN 9 =6

Number of outcomes having a sum that is EVEN and  GREATER THAN 9 ((4,6), (6,4), (5,5), (6,6)) = 4

Now , the Number of outcomes having a sum that is EVEN or GREATER THAN 9  =  (Number of outcomes having EVEN sum)+(Number of outcomes having sum GREATER THAN 9 )-(Number of outcomes having a sum EVEN and  GREATER THAN 9 )

= 18+6-4=20

Now , the probability of randomly rolling 2 standard dice and having a sum that is EVEN or GREATER THAN 9 = $\dfrac{\text{Number of rollings having a sum that is EVEN or GREATER THAN 9 }}{\text{Total outcomes}}\\\\=\dfrac{20}{36}=\dfrac{5}{9}$

Hence, the correct answer is $c.\ \dfrac{5}{9}$