Answer: Choice B. The vertex is (6,-4)
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Work Shown:
Step 1 is to expand out (x-8)(x-4) using the FOIL rule or the box method or the distribution rule
(x-8)(x-4) = x(x-4)-8(x-4)
(x-8)(x-4) = x*x+x*(-4)-8*x-8*(-4)
(x-8)(x-4) = x^2-4x-8x+32
(x-8)(x-4) = x^2-12x+32
So (x-8)(x-4) turns into x^2-12x+32
x^2-12x+32 is the same as 1x^2+(-12x)+32 which is in the form ax^2+bx+c. We see that a = 1, b = -12, c = 32
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Use the values of a & b to find the value of h, which is the x coordinate of the vertex
h = -b/(2*a)
h = -(-12)/(2*1)
h = 12/2
h = 6
Then this is plugged back into the original function to find the y coordinate of the vertex. We can use either (x-8)(x-4) or x^2-12x+32 since they are equivalent expressions
k = y coordinate of vertex
k = f(h) = f(6) since h = 6
f(x) = (x-8)(x-4)
f(6) = (6-8)(6-4)
f(6) = (-2)(2)
f(6) = -4
note that
f(x) = x^2-12x+32
f(6) = (6)^2-12(6)+32
f(6) = 36-72+32
f(6) = -36+32
f(6) = -4
So we get the same result using either expression
So k = f(h) = f(6) = -4
Since h = 6 and k = -4, the vertex is (h,k) = (6,-4). So that's why the answer is choice B.
( -3, 6 ) and ( 2, 6 )
Step-by-step explanation:
So your X axis is ( -3, 2).
And your Y axis is ( 6, 6 ).
So from -3 to 2, you going up +5, and from 6 to 6, you not moving anywhere, which means 0.
So the slope is 5/0
1. S= squash
Z= zucchini
5s + 2z = 1.32
3s + 1z = 0.75. -2 ( 3s + 1z = 0.75)
5s + 2z = 1.32
-6s - 2z = -1.50
-s = -0.12
Squash = 0.12
5s + 2z = 1.32
5(.12) + 2z = 1.32
.60 + 2z = 1.32
2z = 1.32-.60
2z/2 =.72/2
Z= 0.36
Step-by-step explanation:
use bodmas
start with multiplication
-4*10 = -40
5+5/2 - 40
addition next
5 + 5/2 = 7.5
7.5 - 40 = -32.5
