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3 years ago

(12) Help please check my answer

Mathematics

1 answer:

Shkiper50 [21]3 years ago

8 0

Not sure I think maybe its the second choice. Sorry cant be certain.

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Find the measure of each minor arc formed by a regular octagon inscribed in a circle. A. 15° B. 30° C.45° D. 60°

marin [14]

Your octagon has a central angle of 360 deg. Since you're speaking of an octagon, which implies that the octagon is made up of eight triangles, divide 360 deg by 8 to obtain the measure of each minor arc formed.

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3 years ago

Find the unknown size please I really need answers

katen-ka-za [31]

Answer:

z=80°(corresponding angles)

 $x+z=180°(linear \: pair \: ) \\ 80° + x = 180° \\ x= 100°$ 

y=100 ° (alternate angles)

<h2>Hope it helps you<3</h2>

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2 years ago

For case of a 5-item order,how many different ways are there to place an order? For each case,list the number of wheels that wou

Rasek [7]

I don't know the answer

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4 years ago

4. 1/37 of 111 + 1/3 of ? = 0 (1) 3 2) 9 3) 1 4) can not be determined

lisov135 [29]

Answer:

Step-by-step explanation:

1/37 of 111+1/3 of 3= 4

1/37 of 111 +1/3 of 9=6

1/37 of 111 +1/3 of 1=3.3

7 0

2 years ago

Compute the differential of surface area for the surface S described by the given parametrization.

AysviL [449]

With $S$ parameterized by

$\vec r(u,v)=\langle e^u\cos v,e^u\sin v,uv\rangle$

the surface element $\mathrm dS$ is

$\mathrm dS=\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

We have

$\dfrac{\partial\vec r}{\partial u}=\langle e^u\cos v,e^u\sin v,v\rangle$

$\dfrac{\partial\vec r}{\partial v}=\langle -e^u\sin v,e^u\cos v,u\rangle$

with cross product

$\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\langle ue^u\sin v-ve^u\cos v,-ve^u\sin v-ue^u\cos v,e^{2u}\cos^2v+e^{2u}\sin^2v\rangle$

$\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\langle e^u(u\sin v-v\cos v),-e^u(v\sin v+u\cos v),e^{2u}\rangle$

with magnitude

$\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=\sqrt{e^{2u}(u\sin v-v\cos v)^2+e^{2u}(v\sin v+u\cos v)^2+e^{4u}}$

$\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=e^u\sqrt{u^2+v^2+e^{2u}}$

So we have

$\mathrm dS=\boxed{e^u\sqrt{u^2+v^2+e^{2u}}\,\mathrm du\,\mathrm dv}$

8 0

3 years ago