Question

What is the solution set of [1/x-2]<-2

Answer 1

Step-by-step explanation:

$1 \div (x - 2) + 2 < 0$

$(1 + 2x - 4) \div ( x- 2) < 0$

$(2x - 3) \div (x - 2) < 0$

Hence

You have to put:

$2x - 3 > 0$

And

$x - 2 > 0$

Which results in:

$x > 3 \div 2$

And

$x > 2$

The solution is:

$3 \div 2 < x < 2$