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4 years ago

What is a solute in science

Mathematics

2 answers:

TEA [102]4 years ago

4 0

Solute is the substance that is being dissolved in a composition

astraxan [27]4 years ago

3 0

The minor component in a solution, dissolved in the solvent....

like you dissolve 1 spoon salt in 1 glass water..okay then, salt will be solute because it is in less amount and water will be solvent.

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....need help on this

Leona [35]

Answer:

ASA statement

Step-by-step explanation:

In quadrilateral ABCD, diagonal AC bisects $\angle BAD$ and $\angle BCD$ (given)

$In\: \triangle ABC \: and \: \triangle ADC$

$\angle CAB\cong\angle CAD$

(By angle bisector property)

$AC\cong AC.... (common\: side)$

$\angle ACB\cong\angle ACD$

(By angle bisector property)

$\therefore \triangle ABC \cong \triangle ADC$

(By ASA Statement)

3 0

3 years ago

I need help with my final study guide

Citrus2011 [14]

21) Since all angles = 180,
180=66 + 79 + (43 + x)
Subtract (66 + 79) from both sides, you’d get
35= 43 + x
subtract 43 from both sides and x = -8

6 0

3 years ago

israel started to solve a radical equation in this way: square root of x plus 6 − 4 = x square root of x plus 6 − 4 4 = x 4 squa

agasfer [191]

Lets solve our radical equation $\sqrt{x+6}-4=x$ step by step.

Step 1 add 4 to both sides of the equation:

$\sqrt{x+6} -4+4=x +4$

$\sqrt{x} +6=x+4$

Step 2 square both sides of the equation:

$\sqrt{x+6} =x+4$

$\sqrt{x+6}^2 =(x+4)^2$

$x+6=(x+4)^2$

Step 3 expand the binomial in the right hand side:

$x+6=x^2+8x+16$

Step 4 simplify the expression:

$0=x^2+8x-x+16-6$

$x^2+7x+10=0$

Step 5 factor the expression:

$(x+2)(x+5)=0$

Step 6 solve for each factor:

$x+2=0$ or $x+5=0$

$x=-2$ or $x=-5$

Now we are going to check both solutions in the original equation to prove if they are valid:

For $x=-2$

$\sqrt{x+6}-4=x$

$\sqrt{-2+6}-4=-2$

$\sqrt{4}-4=-2$

$2-4=-2$

$-2=-2$

The solution $x=2$ is a valid solution of the rational equation $\sqrt{x+6}-4=x$ .

For $x=-5$

$\sqrt{x+6}-4=x$

$\sqrt{-5+6}-4=-5$

$\sqrt{1}-4=-5$

$1-4=-5$

$-3\neq -5$

Since -3 is not equal to -5, the solution $x=-5$ is not a valid solution of the rational equation $\sqrt{x+6}-4=x$ ; therefore, $x=-5$ is an extraneous solution of the equation.

We can conclude that even all the algebraic procedures of Israel are correct, he did not check for extraneous solutions.

An extraneous solution of an equation is the solution that emerges from the algebraic process of solving the equation but is not a valid solution of the equation. Is worth pointing out that extraneous solutions are particularly frequent in rational equation.

8 0

3 years ago

Someone please help i will give brainliest

baherus [9]

Answer: answers and picture

Step-by-step explanation:

3 0

2 years ago

Evaluate the function. f(x) = –x^2+ 3x + 13 Find f(-10)

oksian1 [2.3K]

Answer:

-117

Step-by-step explanation:

Plug -10 in every time you see "x". Then, I used a calculator to evaluate the function (find the answer). Then, I got -117.

Hope this helped :)

8 0

3 years ago