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anyanavicka [17]
4 years ago
6

What is between 1/3 and 87/100 on a number line

Mathematics
2 answers:
lidiya [134]4 years ago
8 0
0.87..............................
Tanzania [10]4 years ago
3 0
1/3 = 0.333333   87/100 = 0.87
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Could you please check my answers and let me know if they are right?
ANTONII [103]

Answer:

11 is correct

12 should be 51°

Step-by-step explanation:

15/sin(104) = 12/sin(J)

J = 50.917°

8 0
3 years ago
Solve for c in this equation a(b-c)=a/b
morpeh [17]

c=b-1/b

This is the answer

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Solve all the solutions of sinsquarex - cossquarex = 0 in the interval 0,2pi
Lena [83]
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Check the attachment.
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Which is a factor of 4x^2y+24x^2-24y-144?? PLEASE HELP QUICK
Kaylis [27]

4x²y + 24x² - 24y - 144 can be written as :

4x²(y + 6) - 24(y + 6)

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6 0
3 years ago
Jerry starts to save at age 35 for a vacation home that he wants to buy for his 50th birthday. He will contribute $300 each mont
lozanna [386]
If Jerry contributes at the beginning of the month and withdraws at the end of the month, the final contribution earns 1 month's interest. The one before that earns 2 months' interest, so has a value of (1+0.017/12) times that of the last payment. In short, the sum is that of a geometric sequence with first term
  a₁ = 300*(1+0.017/12)
and common ratio
  r = 1+0.017/12

We assume Jerry contributes each month for 15 years, so a total of 180 payments. The sum is given by the formula for the sum of a geometric sequence.
S_{n}=a_{1}\cdot \dfrac{r^{n}-1}{r-1}
Filling in your numbers, this is
S_{180}=300(1+\frac{0.017}{12})\left( \dfrac{(1+\frac{0.017}{12})^{180}}{(\frac{0.017}{12})} \right) \approx 61547

If Jerry's contributions and withdrawal are at the end of the month, this balance is reduced by 1 month's interest, so is $61,460.

_____
We suppose the expected choice is $61,960. This supposition comes from the fact that a handwritten 4 is often confused with a handwritten 9. The usual simple calculation of future value uses end-of-the-month contributions by default. (a₁ = 300)
7 0
3 years ago
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