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IceJOKER [234]
3 years ago
14

Which number is irrational? A) 0.14¯¯¯¯ B) 6√ C) 13 D) 4√

Mathematics
1 answer:
nataly862011 [7]3 years ago
8 0
B is correct.
because this number is around :
2.449489
hope this helps
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What is the percentage between 1192.64 and 819.73
Licemer1 [7]
1192.64-819.73 is 372.91

so... if we take 1192.64 to be the 100%, how much is 372.91 in percentage then?

\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
1192.64&100\\
372.91&p
\end{array}\implies \cfrac{1192.64}{372.91}=\cfrac{100}{p}\implies p=\cfrac{372.91\cdot 100}{1192.64}
3 0
3 years ago
Consider this system of equations:
alexandr1967 [171]
<span>"For which value of k does the system have no real number solutions?"
The answer is 4, because 4+4</span>≠16.
<span>
"For which value of k does the system have one real number solution?"
</span>The answer is -0.25, because the linear line because tangent with the parent function.


<span>"For which value of k does the system have two real number solutions?"
</span>The answer is 2, because the linear function intercepts the parent function 2 times.

- i hope these are the answers you are looking for. 
5 0
3 years ago
The Sugar Sweet Company is going to transport its sugar to market. It will cost $4500 to rent trucks, and it will cost an additi
MariettaO [177]
C(s) = 175s + 4500 or y = 175x + 4500

cost of 12 tons of sugar...
C(12) = 175(12) + 4500
C(12) = 2100 + 4500
C(12) = 6600....so 12 tons of sugar will cost u $ 6600
5 0
3 years ago
Select all statements thats show the correct reasoning for finding 15 divided by 2/9
Anton [14]
No there is nothing here please provide answers

6 0
3 years ago
It is an unfair coin with unknown probability of head and tail. Can you generate even odds using this coin?
Vladimir79 [104]

Answer:

Yes, it can be generated if p = \frac{n}{n+1}, where n is a positive even integer.

Step-by-step explanation:

An odds for an event, is the probability or chance that this event will occur, divided by the probability that it will not occur.

Assume that the probability of getting tail when throwing the coin is p, therefore, the probability of getting a head is (1-p) and the odds for the event of getting tail is \frac{p}{1-p}.

If k is a positive integer, and we assume that the odds of getting a tail are even, then:

\frac{p}{1-p} = 2k

p = 2k - 2kp

p = \frac{2k}{2k+1}

Conclusion: if p = \frac{2k}{2k+1}, for some positive integer k, even odds are generated. For example: p = 2/3, 4/5, 6/7, ...

6 0
3 years ago
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