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shusha [124]
3 years ago
8

What is the answer for 2x+7

Mathematics
1 answer:
satela [25.4K]3 years ago
6 0
Its 11 hope this helps
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What is the answer cos75 degrees=10/x
vova2212 [387]
To find the answer we simply work out the equation.
cos (75) = 10/x

cos (75) * x = 10. Here, I simply multiplied both sides by x to move x to the left hand side of the equation.

x = 10 / cos (75) Here, I divided cos (75) on both sides to move cos (75) to the right hand side of the equation.

The cosine of 75 is 0.92175127, so, 10 / 0.92175127 = 10.8489137
4 0
3 years ago
What is the sum of the amount of pizzas eaten<br>by classes who ate exactly 7⅝​
pogonyaev

Answer:

So, I don't quite have the answer, but I believe you just turn that into an improper fraction and divide it by 8 classes? Decimal Answer.

Step-by-step explanation:

8 0
3 years ago
The necklace has 34 blue beads and 51 white beads. What percentage of the beads on Nina's necklace are blue?
Ivahew [28]

Answer:

40%.

Step-by-step explanation:

Total number of beads = 34 + 51 =  85.

The fraction which are blue = 34/85.

As a percentage this is (34*100) / 85

= 40%.

6 0
3 years ago
Wuts the answer to this problem
Mazyrski [523]

Answer:

Jane is 14 \frac{3}{10}

Step-by-step explanation:

The age of each person increases by a fractional amount.  In order to find Jane's age, you will need to start with Ari's age and then add the additional fractional amounts.  In order to add with fractions, the denominators must be the same.  In the case of Glen, you can figure his age out first:

12 \frac{4}{5} + 1 \frac{1}{6}

5 and 6 have a common denominator of 30, so multiply the numerator and denominator by the same factor and than add:

12 \frac{4}{5} = 12 \frac{24}{30} + 1\frac{1}{6} or 1 \frac{5}{30}= 13 \frac{29}{30}

Taking Glen's age and adding the additional amount for Jane:

13 \frac{29}{30} + 1 \frac{1}{3} or 1 \frac{10}{30}=14 \frac{3}{10}

8 0
3 years ago
An oil storage tank ruptures at time t = 0 and oil leaks from the tank at a rate of
wel
\displaystyle\int_0^{60}r(t)\,\mathrm dt=\int_0^{60}80e^{-0.01t}\,\mathrm dt

Let u=-0.01t so that -100\mathrm du=\mathrm dt. Then the integral becomes

\displaystyle-8000\int_0^{-0.6}e^u\,\mathrm du=8000\int_{-0.6}^0e^u\,\mathrm du=8000(e^0-e^{-0.6})\approx3610\text{ L}
7 0
4 years ago
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