Find two consecutive even natural number whose product is 168

1 answer:

7 0

$2n(2n+2)=168\\
4n^2+4n-168=0\\
n^2+n-42=0\\
n^2+7n-6n-42=0\\
n(n+7)-6(n+7(=0\\
(n-6)(n+7)=0\\
n=6 \vee n=-7\\
-7\not \in \mayhbb{N}\\\\
2n=12\\
2n+2=14$

These numbers are 12 and 14.

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