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NeX [460]
3 years ago
11

Find two consecutive even natural number whose product is 168

Mathematics
1 answer:
Oduvanchick [21]3 years ago
7 0
2n(2n+2)=168\\
4n^2+4n-168=0\\
n^2+n-42=0\\
n^2+7n-6n-42=0\\
n(n+7)-6(n+7(=0\\
(n-6)(n+7)=0\\
n=6 \vee n=-7\\
-7\not \in \mayhbb{N}\\\\
2n=12\\
2n+2=14

These numbers are 12 and 14.
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