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3 years ago

Sari is factoring the polynomial 2x2 + 5x + 3. What is the missing number in her factorization?

Mathematics

2 answers:

sergejj [24]3 years ago

4 0

Answer:

The missing number in Sari's factorization is 3.

Step-by-step explanation:

The given polynomial is,

$=2x^2 + 5x + 3$

From quadratic equations, applying middle term factorization,

$=2x^2 + 2x+3x + 3$

$=2x(x + 1)+3(x + 1)$

$=(2x+3)(x + 1)$

Comparing this to the given expression, the missing number in Sari's factorization is 3.

Greeley [361]3 years ago

4 0

2x² + 5x + 3
2x² + 2x + 3x + 3
2x(x) + 2x(1) + 3(x) + 3(1)
2x(x + 1) + 3(x + 1)
(2x + 3)(x + 1)

The missing number in Sari's factorization is the number 3.

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Step-by-step explanation:

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Total area:

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3 years ago

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r-ruslan [8.4K]

Answer:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

Step-by-step explanation:

Considering the expression

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

Solution Steps:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

$\mathrm{Combine\:the\:fractions\:}\frac{1}{5}-\frac{3}{5}:\quad -\frac{2}{5}$

$=\frac{\frac{4}{5}}{\frac{1}{3}-\frac{2}{5}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}$

$=\frac{4}{5\left(\frac{1}{3}-\frac{2}{5}\right)}$

join $\frac{1}{3}-\frac{2}{5}:\quad -\frac{1}{15}$

$=\frac{4}{5\left(-\frac{1}{15}\right)}$

$\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a$

$=\frac{4}{-5\cdot \frac{1}{15}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}$

$=-\frac{4}{5\cdot \frac{1}{15}}$

$\mathrm{Multiply\:}5\cdot \frac{1}{15}\::\quad \frac{1}{3}$

$=-\frac{4}{\frac{1}{3}}$

$\mathrm{Simplify}\:\frac{4}{\frac{1}{3}}:\quad \frac{12}{1}$

$=-\frac{12}{1}$

$\mathrm{Apply\:rule}\:\frac{a}{1}=a$

$=-12$

Therefore

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

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