Answer:
Therefore the value of bond will triple after 17.72 years.
Step-by-step explanation:
The formula of Compounded continuously
A= Amount after t year
P= initial amount
r = rate of interest
t= time in year.
Given that,
Jacobs college saving are invested in bond that pay 6.2% compounded continuously.
Let after t years the initial amount P will be triple i.e 3P.
Here P=P, A=3P, r= 6.2%=0.062
[ Multiply 
both sides]
Taking ln both sides
[ since 
]
years
Therefore the value of bond will triple after 17.72 years.
The last set is a function
a function can’t have the same two x values
20 and 10.
I can't explain this, because of the fact that I have not learned this yet, and I might be wrong. But I hope I'm not and I hope I helped! ☺
I'm confused too and I'm supposed to be an expert. I'm not entirely sure what frequency density is. We'll just treat this as a histogram.
Let's assume each five minute interval gives a value equal to or proportional to the number of people that finished in that interval.
From 0 to 50 we have 10 intervals; let's just make this into a table
0-5 0
5-10 40
10-15 40
15-20 30
20-25 30
25-30 25
30-35 25
35-40 25
40-45 25
45-50 15
From 0 to 40 that adds up to
0+40+40+30+30+25+25+25 = 215
From 0 to 50 that's
215+25+15 = 255
The fraction less than 40 is 215/255 = 43/51 ≈ .843
Answer: 84.3%
