Yes ok doubling dimensions
When the transverse axis is horizontal, a hyperbola centered at (h,k) has formula (x-h)^2/a^2-(y-k)^2/b^2=1. Plug in h=2, k=1, the formula is (x-2)^2/a^2-(y-1)^2/b^2=1 for some a,b. If the transverse axis is vertical, the formula is (y-h)^2/a^2-(x-k)^2/b^2=1, and (y-2)^2/a^2-(x-1)^2/b^2=1 in our case.
Simply find the average of the entire bunch of numbers.
Then you can go down the list, and easily spot which ones
are smaller than the average and which ones are larger.
To find the average of a bunch of numbers:
-- Add up all of the numbers in the bunch.
-- Divide the sum by how many numbers there are in the bunch.
Sorry I just need points hahahahahhahahhahaaa
Question:
Choose an equivalent expression for 12^3 • 12^9 • 12^4 • 12^2
A. 12^4 B. 12^18 C. 12^35 D. 12^216
Answer:
Step-by-step explanation:
Given
Required
Determine the equivalent
Applying law of indices, we have:
Hence:
