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2 years ago

-32 - 3/5f = -17 How is this worked out?

Mathematics

1 answer:

Andre45 [30]2 years ago

8 0

Answer: f = -25

Step-by-step explanation:

-32 - 3/5f = -17

+ 32 each side

-3/5f = 15

divide each side by -3/5

f = -25

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Use the distributive property to expand the following expression. 2{2.1 x + 3y 1.8}

Alexxandr [17]

Answer:

−3⋅(7x+10y−6)

Step-by-step explanation:

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2 years ago

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Dante’s chocolate bar is 36% cocoa. If the weight of the chocolate bar is 73 grams, how many grams of cocoa does it contain roun

fenix001 [56]

Answer:

26.3 grams

Step-by-step explanation:

36% = 36/100 = 0.36

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2 years ago

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In triangle STU the measure of angle U ie 90°. TU=6.6 US=2.3 find the measure of angle S

Mazyrski [523]

Answer:

70.8 to one decimal place,

or to be exact : 70.7873

Step-by-step explanation:

In right angle triangles, trigonometry functions can be used

here tan out of sin, cos ,tan seems the most appropriate

tan(x) = opposite/adjacent

tan(x) = 6.6/2.3

x = tan^-1 (6.6/2.3)

x = 70.7873

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3 years ago

Degrees =x degrees =y degrees =z Please help

suter [353]

Answer:

x = 64

z = 98

y= 18

Step-by-step explanation:

x = 64

64+z+18 = 180

z = 180-82 = 98

y= 18

6 0

3 years ago

Dennis is cutting construction paper into rectangles for a project he needs to cut one rectangle that is 12 inches times 15 1/4

Nataly_w [17]

Answer:

Dennis need 288.91 square inches of construction paper for his project.

Step-by-step explanation:

Dennis is cutting construction paper into rectangles for a project.

He needs to cut one rectangle that is 12 inches times 15 1/4 inches

First convert the mixed fraction to improper fraction

$15\frac{1}{4} = \frac{(15\times4) + 1}{4} = \frac{61}{4}$

So the area of 1st rectangle is

$A_1 = 12\times \frac{61}{4} = 183 \: in^{2}$

He needs to cut another rectangle that is 10 1/3"" x 10 1/4""

The symbol " means inches

First convert the mixed fraction to improper fraction

$10\frac{1}{3} = \frac{(10\times3) + 1}{3} = \frac{31}{3}$

$10\frac{1}{4} = \frac{(10\times4) + 1}{4} = \frac{41}{4}$

So the area of 2nd rectangle is

$A_2 = \frac{31}{3}\times \frac{41}{4} = 105.91 \: in^{2}$

The total construction paper needed for this project is

$A = A_1 + A_2\\\\A = 183 + 105.91\\\\A = 288.91 \: in^{2}$

Therefore, Dennis need 288.91 square inches of construction paper for his project.

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3 years ago