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3 years ago

-32 - 3/5f = -17 How is this worked out?

Mathematics

1 answer:

Andre45 [30]3 years ago

8 0

Answer: f = -25

Step-by-step explanation:

-32 - 3/5f = -17

+ 32 each side

-3/5f = 15

divide each side by -3/5

f = -25

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Thomas lives 350 miles from the beach. He drives to the beach at an average rate of 50 miles per hour. Use that information and

sweet-ann [11.9K]

Answer:

Step-by-step explanation:

use the equation: y =50x-350 where x is the number of hours driving

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4 0

3 years ago

Y’all someone help pls 5x-3=21-x

attashe74 [19]

5x-3=21-x
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3 years ago

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Consider the initial value problem:

Inessa [10]

Answer:

$\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2$

Step-by-step explanation:

The given initial value problem is;

$y''-5y'+6y=-5\sin(2t)---(1)\\y(0)=-5,y'(0)=2$

Let

$u(t)=y(t)----(2)\\v(t)=y'(t)----(3)$

Differentiating both sides of equation (1) with respect to $t$ , we obtain:

$u'(t)=y'(t)---(4)\\ \\\implies u'(t)=v(t)---(5)$

Differentiating both sides of equation (2) with respect to $t$ gives:

$v'(t)=y''(t)----(6)$

From equation (1),

$y''=5y'-6y-5\sin(2t)\\y''=5v(t)-6u(t)-5\sin(2t)\\\implies v'(t)=5v(t)-6u(t)-5\sin(2t)----(7)$

Putting t=0 into equation (2) yields

$u(0)=y(0)\\\implies u(0)=-5$

Also putting t=0 into equation (3)

$u'(0)=y'(0)\\u'(0)=2$

The system of first order equations is:

$\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2$

3 0

4 years ago

TRUE OR FALSE

Zielflug [23.3K]

Answer:

true

Step-by-step explanation:

8 0

3 years ago

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PLEASE HELP!! I DO NOT UNDERSTAND THIS ONE BIT. PLEASE RESPOND!

Slav-nsk [51]

Substitute z with 3.
3(4)^3
Cube 4 with 3
3(64)
Multiply 3 and 64
=192

4 0

3 years ago