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3 years ago

I really need help with all the questions

Mathematics

1 answer:

nlexa [21]3 years ago

4 0

1. 1,728

2. You can't tell because it doesn't say the amount one serving will serve, and how many servings she is serving, and how many people come to her party. Sorry!!

I hope I helped with the first one!

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If n erasers have a weight of 80 grams, what is the total weight of 50 erasers?

Black_prince [1.1K]

Answer:

$The\ weight\ of\ the\ 50\ erasers\ be\ \frac{4000}{n}\ grams.$

Step-by-step explanation:

As given

if n erasers have a weight of 80 grams .

I.e

n erasera = 80 grams.

1 erasers weight .

$1\ erasers\ weight = \frac{80}{n}$

Now find out the weight of the 50 erasers.

$Weight\ of\ 50\ erasers = \frac{50\times 80}{n}\ grams$

Simplify the above

$Weight\ of\ 50\ erasers = \frac{4000}{n}\ grams$

$Therefore\ the\ weight\ of\ the\ 50\ erasers\ be\ \frac{4000}{n}\ grams.$

6 0

3 years ago

Read 2 more answers

PLS HELP ASAP WORTH 99 POINTS!

chubhunter [2.5K]

Answer:

I’m pretty sure it’s 10

Step-by-step explanation:

Because the formula is something like baseXhight divided by two. and 2 times sixty is 120 so 120/12=10 that divided by 2 is five so the answer is either 5 or 10

7 0

3 years ago

Read 2 more answers

Anyone have the answer for this

sergiy2304 [10]

$\huge\bold{Given:}$

Length of the base = 16 km.

Length of the hypotenuse = 34 km. $\huge\bold{To\:find:}$

✎ The length of the missing leg '' $a$ ".

$\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}$

The length of the missing leg "a" is $\boxed{30\:km}$ .

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}$

Using Pythagoras theorem, we have

$({perpendicular})^{2} + ({base})^{2} = ({hypotenuse})^{2} \\ ⇢ {a}^{2} + ({16 \: km})^{2} = ({34 \: km})^{2} \\ ⇢ {a}^{2} + 256 \: {km}^{2} = 1156 \: {km}^{2} \\ ⇢ {a}^{2} = 1156 \: {km}^{2} - 256 \: {km}^{2} \\ ⇢ {a}^{2} = 900 \: {km}^{2} \\ ⇢a \: = \sqrt{900 \: {km}^{2} } \\ ⇢a = \sqrt{30 \times 30 \: {km}^{2} } \\ ⇢a = 30 \: km$

$\sf\blue{Therefore,\:the\:length\:of\:the\:missing\:leg\:"a"\:is\:30\:km.}$

$\huge\bold{To\:verify :}$

$( {30 \: km})^{2} + ({16 \: km})^{2} =( {34 \: km})^{2} \\ ⇝900 \: {km}^{2} + 256 \: {km}^{2} = 1156 \: {km}^{2} \\⇝1156 \: {km}^{2} = 1156 \: {km}^{2} \\ ⇝L.H.S.=R. H. S$