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3 years ago

Compare metals to nonmetals. Include where they are located on the periodic table as well as three properties of each.

Chemistry

1 answer:

Genrish500 [490]3 years ago

4 0

Answer:

Difference between metals and non metals.

1) Metals are good conductors of heat and electricity while non metals are poor conductors.

2) Metals are hard while non metals are soft.

3) Metals have shiny surface while non metals have not.

Examples of metals are sodium and iron while non metals are chlorine and oxygen.

Location in the periodic table.

Metals are present on the left side of the table while non metals are present on the right side of periodic table.

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If 6 moles of A and 2 moles of B are reacted, what is the maximum number of moles of C that can be formed

MaRussiya [10]

The question is incomplete, here is the complete question:

Suppose the reaction is:

$A+2B\rightarrow C$

If 6 moles of A and 2 moles of B are reacted, what is the maximum number of moles of C that can be formed

<u>Answer:</u> The maximum amount of C produced will be 1 mole

<u>Explanation:</u>

We are given:

Moles of A = 6 moles

Moles of B = 2 moles

For the given chemical reaction:

$A+2B\rightarrow C$

By Stoichiometry of the reaction:

2 moles of B reacts with 1 mole of A

So, 2 moles of B will react with = $\frac{1}{2}\times 2=1$ mole of A

As, As, given amount of A is more than the required amount. So, it is considered as an excess reagent.

Thus, B is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of B produces 1 mole of C

So, 2 moles of given B will produce $=\frac{1}{2}\times 2=1mol$ of C

Hence, the maximum amount of C produced will be 1 mole

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3 years ago

Aluminum has a specific heat of 0.902 j/gC. How much heat is lost when a piece of aluminum with a mass of 23.984 g cools from a

Marizza181 [45]

Answer:

Q = - 8501.99 j

Explanation:

Given data:

Specific heat of Al = 0.902 j/g.°C

Heat lost = ?

Mass of sample = 23.984 g

Initial temperature = 415°C

Final temperature = 22°C

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 22°C - 415°C

ΔT = -393°C

Q = m.c. ΔT

Q = 23.984 g× 0.902 j/g.°C × -393°C

Q = - 8501.99 j

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Answer:

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Explanation:

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Answer:

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