How many 10p pieces in a pound?

The first and second terms of a linear sequence (A.p) are 3 and 8 respectively. Please determine the least Number of terms of Ap

Alla [95]

Answer:

To rewrite your question, you are looking for the smallest that fulfills the inequality:

∑=1>250

First, we must find the sequence in explicit form. We can think of it as a line we are trying to get the slope-intercept form of. We have the points (1, 3) and (2, 8). Therefore, the slope is 8−32−1=51=5 . Now we just need the y-intercept. We can find it through substitution:

=5+

In order to solve for , we can plug in one of the points that we were already given. I will choose the point (1, 3). Note that this point just means that when =1 , =3 .

3=5(1)+

3=5+

=−2

Now for the original question.

∑=1(5−2)>250

((5(1)−2)+(5()−2)2)>250

(5+12)>250

522+12>250

2+15>100

2+15+1100>100+1100

(+110)2>100+1100

(+110)2>10001100

+110>±10001100‾‾‾‾‾‾‾√

+110>±11010001‾‾‾‾‾‾√

>−110±11010001‾‾‾‾‾‾√

Since we are looking for the smallest value, we will subtract for the plus or minus sign.

>−110−11010001‾‾‾‾‾‾√≈−10

Since that is negative, we will have to add instead.

>−110+11010001‾‾‾‾‾‾√≈9.9

Therefore, the smallest integer that makes sense and satisfies the inequality is 10.

So, the first 10 numbers must be added.

Honestly, it would have been quicker just to brute-force this.

Step-by-step explanation:

Have a good day

8 0

3 years ago

The granola summer buys used to cost $6.00 per pound but it has been marked up %15 A. How much did it cost summer to buy 2.6 pou

Maksim231197 [3]

The granola summer buys used to cost $6.00 per pound but it has been marked up %15 Question: How much did it cost summer to buy 2.6 pounds of granola at the old price.=> previous price of granola = 6.00 dollars per pound=> marked up 15% = 15% /100% = .15Solve:=> 6 * .15 = .9=> 6 + .9 = 6.9 dollars per poundNow, you want to buy 2.6 pounds=> 6.9 * 2.6 = 17.94 dollars <span>
</span>

3 0

3 years ago

A high school has 44 players on the football team. The summary of the players' weights is given in the box plot. Approximately,

Marina CMI [18]

Answer:

Step-by-step explanation:

The missing image is attached below.

From the given information

The number of players is 44.

From the box plot;

The minimum weight = 154 pounds

The first quartile Q₁ = 159 which is 25% of the data below 159 pounds.

The second quartile Q₂ = 213 which is 50% of the data below 213 pounds

The third quartile Q₃ = 253 which is 75% of the data below 253 pounds

The maximum weight = 268 pounds.

Here, the value of 213 is the middle value and which signifies the median.

The 50% of the data are located both on the left side and the right side of the median.

Thus, the percentage of players weighting greater than or equal to 213 pounds is 50%.

7 0

3 years ago

Write the expression using exponents.<br><br>23 · y · y · y · y

Ostrovityanka [42]

Answer:

Exponent: 23y^4

3 0

3 years ago

The null space for the matrix is span{A,B} where:_____.

xz_007 [3.2K]

Answer:

A is spanned by vector.

Step-by-step explanation:

The null space of matrix is set of all solutions to matrix. The linearly independent vectors forms subset which are spanned and forms the null space. The null space of vector can be found by reducing its echelon. The non zero rows formed are the null spaces of matrix.

3 0

3 years ago