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Alisiya [41]
4 years ago
15

What is greater 7/12 0.75 or 5/6

Mathematics
1 answer:
blsea [12.9K]4 years ago
7 0
7/12=.58
5/6= .83
soooo
if the numbers are .58, .83 and .75 your order would be 
.58, .75, .83
in other words
7/12, .75, 5/6
if your just looking for the biggest number your answer would be
5/6
hope this helps!
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What is the solution to the inequality 4(2x + 2) + 12 7 100?
soldi70 [24.7K]

Answer:

x>10

Step-by-step explanation:

4(2x + 2) + 12 > 100

Subtract 12 from each side

4(2x + 2) + 12 -12> 100-12

4(2x + 2) > 88

Divide by 4

4/4(2x + 2) > 88/4

2x+2 > 22

Subtract 2

2x+2-2 > 22-2

2x> 20

Divide by 2

2x/2 >20/2

x>10

7 0
3 years ago
Read 2 more answers
Suppose M is the midpoint of Segment AB, P is the midpoint of Segment AM, and Q is the midpoint of segment PM.
DerKrebs [107]

The coordinates of M, P and Q in terms of a and b are M = \frac{1}{2}\cdot a + \frac{1}{2}\cdot b, P = \frac{3}{4}\cdot a + \frac{1}{4}\cdot b and Q = \frac{1}{8}\cdot a - \frac{1}{8}\cdot b, respectively.

In this question we are going to use definitions of vectors and product of a vector by a scalar. Based on the information given on statement, we have the following vectorial formulas:

Location of M

\overrightarrow{AM} = \frac{1}{2}\cdot \overrightarrow{AB}

\vec M - \vec A = \frac{1}{2}\cdot \vec B - \frac{1}{2}\cdot \vec A

\vec M = \frac{1}{2}\cdot \vec A +\frac{1}{2}\cdot \vec B

M = \frac{1}{2}\cdot a + \frac{1}{2}\cdot b

Location of P

\overrightarrow{AP} = \frac{1}{2}\cdot \overrightarrow{AM}

\vec P - \vec A = \frac{1}{2}\cdot \vec M - \frac{1}{2}\cdot \vec A

\vec P = \frac{1}{2}\cdot \vec A +\frac{1}{2}\cdot \vec M

\vec P = \frac{3}{4}\cdot \vec A  + \frac{1}{4}\cdot \vec B

P = \frac{3}{4}\cdot a + \frac{1}{4}\cdot b

Location of Q

\overrightarrow{QM} = \frac{1}{2}\cdot \overrightarrow{PM}

\vec M - \vec Q = \frac{1}{2}\cdot \vec M - \frac{1}{2}\cdot \vec P

\vec Q = \frac{1}{2}\cdot \vec P - \frac{1}{2}\cdot \vec M

\vec Q = \frac{1}{2}\cdot \left(\frac{3}{4}\cdot \vec A + \frac{1}{4}\cdot \vec B\right) -\frac{1}{2}\cdot \left(\frac{1}{2}\cdot \vec A + \frac{1}{2}\cdot \vec B\right)

\vec Q = \frac{1}{8}\cdot \vec A -\frac{1}{8}\cdot \vec B

Q = \frac{1}{8}\cdot a - \frac{1}{8}\cdot b

The coordinates of M, P and Q in terms of a and b are M = \frac{1}{2}\cdot a + \frac{1}{2}\cdot b, P = \frac{3}{4}\cdot a + \frac{1}{4}\cdot b and Q = \frac{1}{8}\cdot a - \frac{1}{8}\cdot b, respectively.

We kindly invite to check this question on midpoints: brainly.com/question/4747771

4 0
2 years ago
The first one I don't get can anyone help me
makkiz [27]
The answer is A. -12°F. we can calculate it by subtracting the initial temperature from the final temperature, i.e. -7-5 = -12
8 0
3 years ago
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Ken started a savings account for school. He plans on spending 10% of the money he earns for leisure activities. He needs to hav
uranmaximum [27]

Answer:

$2,400

Step-by-step explanation:

Ken intends to start a savings account

10% = leisure spending

This means 90% = Expenses for school

Let us represent the amount he must save as : x

Hence in other for him to have $2,160 in his savings account, the amount Ken must earn is calculated as:

90/100 × x = $2,160

Cross Multiply

90x = $2,160 × 100

x = ($2,160 × 100) ÷ 90

x =$2,400

Therefore, the amount Ken has to earn to have the amount needed for school is $2,400

5 0
3 years ago
What is the range of the function fx 1/3 |x-1| -2​
kramer

Answer:

Step-by-step explanation:

5 0
4 years ago
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