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3 years ago

8

Tyler mixes 55 kilograms of gravel with 11 kilograms of cement . How many kilograms of gravel does Tyler need for each kilogram

of cement?

1 answer:

storchak [24]3 years ago

4 0

Answer:

5

Step-by-step explanation:

55/11=5

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R is the midpoint of OP and QR is perpendicular to OP in the diagram below

dezoksy [38]

Answer:

24 in

Step-by-step explanation

Using pythagorean theorem, since OP is 20 inches and has a midpoint. RP= 10 and OR=10. The hypotenuse is given as 26 so do 26^2=10^2+a. 676= 100+a^2, subtract 100 from both sides. square root of 576 is 24

7 0

3 years ago

USPS charges a flate rate of $5.50 for the 1st pound of shipping, plus $1.35 for each additional pound. FedEx charges $8.00 for

Rasek [7]

usps is cheaper

Step-by-step explanation:

usps equals 6 dollars 85 cents and fedex charges 9 dollars and 10 cents

5 0

3 years ago

Read 2 more answers

Population Growth Using 20th-century U.S. census data,

asambeis [7]

The population of Ohio will be 10 million in the year 1970

The population growth of Ohio is represented by the function:

$P(t)=\frac{12.79}{1+2.402e^{-}0.0309t}$

P is the population in millions

t is the number of years since 1900

To find the year that the population of Ohio will be 10 million, substitute P = 10 into the function P(t) and solve for t

$10=\frac{12.79}{1+2.402e^{-}0.0309t}\\\\10(1+2.402e^{-}0.0309t)=12.79\\\\1+2.402e^{-}0.0309t=\frac{12.79}{10} \\\\1+2.402e^{-}0.0309t=1.279\\\\2.402e^{-}0.0309t=1.279-1\\\\2.402e^{-}0.0309t = 0.279\\\\e^{-}0.0309t =\frac{0.279}{2.402} \\\\e^{-}0.0309t =0.116\\\\-0.0309t=ln0.116\\\\-0.0309t=-2.154\\\\t=\frac{-2.154}{-0.0309} \\\\t=69.7$

t = 70 years (to the nearest whole number)

70 years after 1900 will be 1970

Therefore, the population of Ohio will be 10 million in the year 1970

Learn more here: brainly.com/question/25504185

5 0

2 years ago

In a sample of 679 new websites registered on the Internet, 42 were anonymous (i.e., they shielded their name and contact inform

Semmy [17]

Answer:

95% Confidence interval: (0.0429,0.0791)

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 679

Number of anonymous websites, x = 42

$\hat{p} = \dfrac{x}{n} = \dfrac{42}{679} = 0.0618$

95% Confidence interval:

$\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.96$

Putting the values, we get:

$0.0618\pm 1.96(\sqrt{\dfrac{0.0618(1-0.0618)}{679}}) = 0.0618\pm 0.0181\\\\=(0.0429,0.0791)$

is the required confidence interval for proportion of all new websites that were anonymous.

8 0

3 years ago

Nate spent $28 on 2 dvds.at this rate how much would 5 dvds cost him

Anuta_ua [19.1K]

2=28 divide both get 14 . So each cd is 14$. So now 28+28=56 (4 cd's) plus 14 (1 more cd) =5 so 5 is 70.

7 0

3 years ago