The first one, WX is perpendicular to ZY and WX is parallel to AB
Answer:
The minimum sample size is 1867 observations.
Step-by-step explanation:
We need to construct an 85% confidence interval that has an error less than 0.06. It means that the difference between the upper limit (UL) and the lower limit (LL) has to be 0.06.
![UL-LL= e =0.06](https://tex.z-dn.net/?f=UL-LL%3D%20e%20%3D0.06)
![UL-LL= e =0.06\\X+z*s/\sqrt{n} -(X-z*s/\sqrt{n}) = e\\2*z*s/\sqrt{n}=e\\](https://tex.z-dn.net/?f=UL-LL%3D%20e%20%3D0.06%5C%5CX%2Bz%2As%2F%5Csqrt%7Bn%7D%20-%28X-z%2As%2F%5Csqrt%7Bn%7D%29%20%3D%20e%5C%5C2%2Az%2As%2F%5Csqrt%7Bn%7D%3De%5C%5C)
The only variable we can adjust is the number of observations (n)
![2*z*s/\sqrt{n}=e\\\\\sqrt{n}=\frac{2*z*s}{e}\\\\ n=(\frac{2*z*s}{e})^{2}=\frac{4*z^{2} *s^{2} }{e^{2} }](https://tex.z-dn.net/?f=2%2Az%2As%2F%5Csqrt%7Bn%7D%3De%5C%5C%5C%5C%5Csqrt%7Bn%7D%3D%5Cfrac%7B2%2Az%2As%7D%7Be%7D%5C%5C%5C%5C%20n%3D%28%5Cfrac%7B2%2Az%2As%7D%7Be%7D%29%5E%7B2%7D%3D%5Cfrac%7B4%2Az%5E%7B2%7D%20%2As%5E%7B2%7D%20%7D%7Be%5E%7B2%7D%20%7D)
For a 85% confidence interval, the z-score is 1.440.
The estimated variance (s^2) is 0.81.
The error e is 0.06.
![n= 4*(1.440)^{2} *0.81/(0.06)^{2} \\\n=4*2.0736*0.81/0.0036= 6.7184 / 0.0036 = 1866.24](https://tex.z-dn.net/?f=n%3D%204%2A%281.440%29%5E%7B2%7D%20%2A0.81%2F%280.06%29%5E%7B2%7D%20%5C%5C%5Cn%3D4%2A2.0736%2A0.81%2F0.0036%3D%206.7184%20%2F%200.0036%20%3D%201866.24)
The sample has to be at least of 1867 observations.
Answer:
1.6
Step-by-step explanation:
First things first is to find what line QP corresponds with which is line MN
After that you find what multiplied into 5 would make it 2. The easiest way of ding so is to divide 2 by 5 which is 0.4. Now you want to find what line PR corresponds with which is OM. Now you multiply 4 (length of line OM) by 0.4 to find the length of line PR which is x. So now line PR is equal to 1.6 and x. Which also means that x=1.6
Answer:
X=5
mde=e
mef=5
mdfg=77
Step-by-step explanation: