All categories

4 years ago

-2x + 7 > 172 I need help please

Mathematics

1 answer:

Nataly_w [17]4 years ago

5 0

Answer: x>165/2

Step-by-step explanation:

2x + 7 > 172

Subtract 7 from both sides.

2x>172−7

Simplify 172−7 to 165.

2x>165

Divide both sides by two

x>165/2

Hope this helps, HAVE A BLESSED AND WONDERFUL DAY! As well as a great Superbowl Weekend! :-)

- Cutiepatutie ☺❀❤

You might be interested in

Roxanne, Roxane all she wanna do is party all night god danm Roxanne

AfilCa [17]

Never gonna love me but it's alright

She think I'm a a] hole

She think I'm a player

She keep running back though

Only cause I pay up

Roxanne

All she wanna do is party all night

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

LAST QUESTION PLS HELP ME

yaroslaw [1]

The third one....
Sam amount increase each day by 1.75 so 1.75x and when you plug in 9....
1.75(9)=15.75

8 0

3 years ago

PERSONALLY I thought it would be 98 Bc like yk..BUT I FEEL LIKE IM WRONGsend help beggin cryin throwin up I hate geometry so muc

melomori [17]

Answer:

X=98(Being corresponding angle)

You are correct

4 0

2 years ago

2. y = -2x² + 8x Axis of Symmetry: Vertex: Domain: Range:

worty [1.4K]

Answer:

Part 1) The axis of symmetry is x=2

Part 2) The vertex is the point (2,8)

Part 3) The domain is all real numbers

Part 4) The range is all real numbers less than or equal to 8

Step-by-step explanation:

we have

$y=-2x^{2}+8x$

This is a vertical parabola open downward (because the leading coefficient is negative)

The vertex represent a maximum

step 1

Find the vertex

Convert the quadratic equation in vertex form

Factor -2 leading coefficient

$y=-2(x^{2}-4x)$

Complete the square

$y=-2(x^{2}-4x+4)+8$

rewrite as perfect squares

$y=-2(x-2)^{2}+8$

The vertex is the point (2,8)

step 2

Find the axis of Symmetry

we know that

In a vertical parabola, the axis of symmetry is equal to the x-coordinate of the vertex

the vertex is the point (2,8)

therefore

The axis of symmetry is x=2

step 3

Find the domain

The domain of the quadratic equation is the interval ------> (-∞,∞)

The domain is all real numbers

step 4

Find the range

The range of the quadratic equation is the interval ------> (-∞,8]

$y\leq 8$

The range is all real numbers less than or equal to 8

5 0

3 years ago

Which equation can be used to graph the line that passes through (6, 15) and is perpendicular to the graph of y-7=1/2(x+2)

Westkost [7]

Answer:

y = -2x + 27

Step-by-step explanation:

Firstly, we shall need to reform the given line equation;

y-7 = 1/2 ( x + 2)

y - 7 = x/2 + 1

y = x/2 + 1 + 8

y = x/2 + 8

Comparing this with y = mx + c

where m is the slope, then the slope of the line is 1/2

Since the line we are looking for has a slope perpendicular to this line, it means that the product of their slopes is -1

m1 * m2 = -1

1/2 * m2 = -1

m2 = -2

So we want an equation with slope -2 passing through (6,15)

we use the point slope method here;

y-y1 = m(x-x1)

y-15 = -2(x-6)

y-15 = -2x + 12

y= -2x + 12 + 15

y = -2x + 27

6 0

3 years ago