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3 years ago

Probability of rolling a 10, 11 or 12 on a 12 sided die

2 answers:

7 0

10, 11, and 12 are 3 options out of the 12 sides. That is 3 out of 12, which is 3/12.
If you simplify that, it is 1/4.
In decimal form it is 0.25, and in percent form it is 25%.
Hope this helps!

mario62 [17]3 years ago

4 0

There is a 1 in four chance of rolling those 3 numbers. You know this because there is a 3/12 chance of of rolling a 10,11, or 12. Simplify the fraction and you get 1/4.

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Find the focus and directrix of y=4x^2

Mkey [24]

Hello there

the answer is

(0,1/16)

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2 years ago

What is –36° converted to radians?

Stells [14]

let's recall that there are 180° in π radians, thus

$\bf \begin{array}{ccll} degrees&radians\\ \cline{1-2} 180&\pi \\ -36&x \end{array}\implies \cfrac{180}{-36}=\cfrac{\pi }{x}\implies -5=\cfrac{\pi }{x}\implies x=\cfrac{\pi }{-5}\implies x=-\cfrac{\pi }{5}$

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3 years ago

A sales team estimates that the number of new phones they will sell is a function of the price that they set. They estimate that

USPshnik [31]

Answer:

$204

Step-by-step explanation:

The question is at what price x will the company maximize revenue.

The revenue function is:

$R(x) = 4,080x-10x^2$

The price for which the derivate of the revenue function is zero is the price the maximizes revenue:

$R(x) = 4,080x-10x^2\\\frac{dR(x)}{dx}=0=4,080-20x\\x=\frac{4,080}{20}\\ x=\$204$

The company will maximize its revenue when the price is $204.

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3 years ago

Lin is making two pans of brownies. She lines the bottom of her first pan with aluminum foil. The area of the rectangular piece

Gemiola [76]

Answer: 2 1/2 inches

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2 years ago

A tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24. The players were still hungry so the coa

g100num [7]

The cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8

<h3><u>Solution:</u></h3>

Let "f" be the cost of 1 fries

Let "h" be the cost of 1 hamburger

<em><u>Given that, tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24</u></em>

8 x cost of 1 hamburger + 5 x cost of 1 fries = 24

$8 \times h + 5 \times f = 24$

8h + 5f = 24 -------- eqn 1

<em><u>The players were still hungry so the coach bought six more hamburgers and two more fries for $16.60</u></em>

6 x cost of 1 hamburger + 2 x cost of 1 fries = 16.60

$6 \times h + 2 \times f = 16.60$

6h + 2f = 16.60 ------ eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Multiply eqn 1 by 2

16h + 10f = 48 ------ eqn 3

Multiply eqn 2 by 5

30h + 10f = 83 -------- eqn 4

<em><u>Subtract eqn 3 from eqn 4</u></em>

30h + 10f = 83

16h + 10f = 48

( - ) ----------------------

14h = 35

Substitute h = 2.5 in eqn 1

8(2.5) + 5f = 24

20 + 5f = 24

5f = 4

Thus cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8

5 0

3 years ago