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Simora [160]
4 years ago
15

Divide (-5w^10+10w^8+5w^6)/(5w^5)

Mathematics
1 answer:
Nesterboy [21]4 years ago
6 0
The easiest way to do this is to split that numerator up into each of its individual expressions over the denominator, like this:  \frac{-5w^{10}}{5w^5}+ \frac{10w^8}{5w^5}+ \frac{5w^6}{5w^5}  and then divide each expression one at a time.  In the first expression, -5 diivided by 5 = -1.  Now for the exponents.  As long as the base is the same you will subtract the exponents, lower from upper.  Our bases are all w's, so we're good.  w^{10-5}=w^5  so that expression is  -w^5.  Now for the second expression.  10 divided by 5 is 2, and, using our rules for dividing exponents with like bases,  w^{8-5}=w^3.  So that expression is  2w^3.  For the last term there, 5 divided by 5 is 1, and  w^{6-5}=w^1=w.  Now we will put all of them together to get a final solution of  -w^5+2w^3+w.  There you go!
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