Question

Identify the vertical asymptotes of f(x) = 10/(x^2-7x-30)?

Answer 1

$f(x) = \frac{10}{ {x}^{2} - 7x - 30 }$
Vertical asymptote refers to the values that x cannot be.
Factorise the denominator to make it into
$\frac{10}{(x - 10)(x + 3)}$
As the denominator can't be equal to 0, x-10 cant be 0, and x+3 can't be 0 either;

So x can't be 10, or -3
Therefore the vertical asymptotes are x=10 and x=3.

Hope this helped