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miss Akunina [59]
3 years ago
14

Ben has 4 unit cubes. how many different rectangular prisms can he make using all 4 unit cubes

Mathematics
2 answers:
kvv77 [185]3 years ago
7 0

Using 4 unit cubes 2 rectangular prisms could be made.

One with dimensions, 4\; unit \;by \;1 unit\; by\; 1 \; unit.

The other with dimensions, 2\; unit \;by \;2 unit\; by\; 1 \; unit.

The figure of a rectangular prism is given below.


miskamm [114]3 years ago
4 0
2 rectangular prisms.

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Find all the factors of 45
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Answer:

So, the factors of 45 are 1, 3, 5, 9, 15 and 45.

Common Factors.

Prime Numbers.

Highest Common Factor.

Step-by-step explanation:

45 is a composite number. 45 = 1 x 45, 3 x 15, or 5 x 9. Factors of 45: 1, 3, 5, 9, 15, 45. Prime factorization: 45 = 3 x 3 x 5, which can also be written 45 = 3² x 5.

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Which pair of numbers is relatively prime?
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Not A.(17 is a common factor)
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3 0
3 years ago
PLEASE HELP QUICKLY: (FIRST ANSWER GETS BRAINLIEST)
kodGreya [7K]

Answer:

Buy the batteries and stereo online:  

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6.99-5.00 = $1.99  

99.98+1.99=$101.97  

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7.97*3= $23.85  

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<u><em>(CREDIT: Hussain514)</em></u>

8 0
3 years ago
Mia needs to bring ar least 25 pieces of fruit to the school picnic. She suggested both apples and oranges and was told to be su
SOVA2 [1]
I think  x + y ≥ 25, x ≥ 10, y ≥ 0
7 0
3 years ago
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Sketch the region enclosed by y=3x and y=x^2 . Then find the area of the region.
kolezko [41]

Answer:

A=4.5u^2

Step-by-step explanation:

The integral of a function gives you the area under the curve, the subtraction of one of the areas from the other will give you the area in between.

The limits of integration are the points where the curves intersect each other(take the curves has a system of equation and solve for x and y):

y=3x, y=x^2\\3x=x^2\\x^2-3x=0\\x(x-3)=0\\x_1=0\\x-3=0\\x_2=3

y_1=3x_1=3(0)=0\\y_2=3x_2=3(3)=9

The integral will be the subtraction of the curve y=3x and y=x^2  (In the graph you can see y=3x is the upper curve):

\int\limits^3_0 {3x-x^2} \, dx =\left\frac{3x^2}{2}-\frac{x^3}{3}\right|^3_0=\frac{3(3)^2}{2}-\frac{(3)^3}{3}-\left(\frac{3(0)^2}{2}-\frac{(0)^3}{3}\right)\\\int\limits^3_0 {3x-x^2} \, dx =\frac{27}{2}-\frac{27}{3} =13.5-9=4.5u^2

6 0
3 years ago
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