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SpyIntel [72]
3 years ago
15

Here is a centimetre square grid. Draw a shape with an area of 11cm squared.

Mathematics
2 answers:
aksik [14]3 years ago
6 0

Hi

Answer in photo

NOTE: I'm not sure the answer may not be true

Good Luck

#Turkey

Fofino [41]3 years ago
3 0

Answer:

Here’s one shape that works.

Step-by-step explanation:

The blue L-shaped figure is one of many solutions.

The area of the long side of the L is 10 cm × 1 cm = 10 cm².

The area of the short side is 1 cm × 1 cm = 1 cm².

The total area of the L is 10 cm² + 1 cm² = 11 cm².

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I need help on these questions can u make sure u do all of them cuz some people just only do one problem.
charle [14.2K]

Answer:

Ans. = 18

Step-by-step explanation:

= -1 (-1)(-3)(-6)

= 1×18

=18

5 0
2 years ago
Read 2 more answers
An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s
Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>

Step-by-step explanation:

Given:

Initial speed of debris is, s=120\ ft/s

The height 'h' of the debris above the ground is given as:

h(t)=-16t^2+120t

As per question, h(t)=56\ ft. Therefore,

56=-16t^2+120t

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0

Using quadratic formula to solve for 't', we get:

t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s

Therefore, the debris will reach a height of 56 ft twice.

When time t=0.5\ s during the upward journey, the debris is at height of 56 ft.

Again after reaching maximum height, the debris falls back and at t=7\ s, the height is 56 ft.

5 0
3 years ago
What is an<br> equation of the line that passes through the points (-4, -1) and (3,-8)?
Kaylis [27]

Answer:

y=-x-5

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-8-(-1))/(3-(-4))

m=(-8+1)/(3+4)

m=-7/7

m=-1

y-y1=m(x-x1)

y-(-1)=-1(x-(-4))

y+1=-1(x+4)

y+1=-x-4

y=-x-4-1

y=-x-5

Please mark me as Brainliest if you're satisfied with the answer.

6 0
2 years ago
You run out of gas and measure the amount of gas it takes to fill the tank. Is this data a type discrete or continuous
ziro4ka [17]

I think it is continuous

7 0
2 years ago
The numbers -5,7,-18,and 0 are examples of
olga_2 [115]

Answer:

real numbers

Step-by-step explanation:

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2 years ago
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