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4 years ago

112 is 70% of what help

2 answers:

6 0

If you would like to know 70% of what is 112, you can calculate this using the following steps:

70% of x is 112
70% * x = 112
70/100 * x = 112 /*100/70
x = 112 * 100/70
x = 160

Result: 70% of 160 is 112.

NeX [460]4 years ago

3 0

112 = 0.7 × X
Divide both sides by 0.7.
112 ÷ 0.7 = 160
112 is 70% of 160

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Diego is 165 cm tall. Andre is 1.7 . tall. Who is taller Diego or Andre?

ycow [4]

Answer:

Andre is taller.

Step-by-step explanation:

I assume Andre's height is 1.7 m.

Let's convert Andre's height to cm.

1 m = 100 cm

1.7 m = 1.7 * 1 m = 1.7 * 100 cm = 170 cm

Andre is 170 cm tall. Diego is 165 cm tall.

Since 170 cm > 165 cm, Andre is taller.

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2 years ago

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2 years ago

Solve for K 2(k - 5) + 3k = k + 6

Alexandra [31]

Answer:

k = 4

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtract Property of Equality

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

2(k - 5) + 3k = k + 6

Step 2: Solve for k

Distribute 2: 2k - 10 + 3k = k + 6
Combine like terms: 5k - 10 = k + 6
Subtract k on both sides: 4k - 10 = 6
Add 10 on both sides: 4k = 16
Divide 4 on both sides: k = 4

Step 3: Check

Plug in k into the original equation to verify it's a solution.

Substitute in k: 2(4 - 5) + 3(4) = 4 + 6
(Parenthesis) Subtract: 2(-1) + 3(4) = 4 + 6
Multiply: -2 + 12 = 4 + 6
Add: 10 = 10

Here we see that 10 does indeed equal 10.

∴ k = 4 is the solution to the equation.

3 0

3 years ago

A father is 60 years old and his son is half his age. How old was the boy when his father was four times his age?

Anni [7]

Hey there! I'm happy to help!

We see that the father is 60 years old, and the son is half of that age, so this means that the son is 30 years old.

We want to see the age the son was at when the father was four times his age. We know that the father is thirty years older than him, so we can write this equation with s representing the age of the son.

s+30=4s (30 years older than the son is equal to to four times the son's age at the time)

We subtract 30 from both sides.

s=4s-30

We subtract 4s from both sides.

-3s=-30

We divide both sides by -3.

s=10

Therefore, the boy was 10 when his father was four times his age. This is because his father would have been 40 because that is 30 more years than 10, and it is four times ten!

Have a wonderful day! :D

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3 years ago