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4 years ago

-2(bx-5)=16 The value of x in terms of b is? That value of x when b is 3?

Mathematics

1 answer:

grin007 [14]4 years ago

7 0

Answer:

Step-by-step explanation:

Let's solve for b.

−2(bx−5)=16

Step 1: Add -10 to both sides.

−2bx+10+−10=16+−10

−2bx=6

Step 2: Divide both sides by -2x.

−2bx/−2x=6/−2x

b=−3x

Answer:

b=−3x

———————————————————

Let's solve for x.

−2(bx−5)=16

Step 1: Add -10 to both sides.

−2bx+10+−10=16+−10

−2bx=6

Step 2: Divide both sides by -2b.

−2bx/−2b=6/−2b

x=−3b

Answer:

x=−3b

Hope this helps you out

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The width of a rectangle is 6n - 2.5 feet and the length is 2.5 + 8 feet. Find the perimeter of the rectangle.

ludmilkaskok [199]

I was thinking the measurement for ;length should be 2.5n + 8 feet since width is 6n -2.5 feet , but you gave 2.5+ 8 feet, so i will solve it in both ways

Answer: Perimeter = 5 + 12n + 11 feet ; Perimeter = 17n+ 11 feet

Step-by-step explanation:

Using Length = 2.5+ 8 feet,

Perimeter of a rectangle is calculated as 2( l+ b)

Given that width=6n - 2.5 feet

length =2.5 + 8 feet

Perimeter =2( l+ b)= 2L + 2B

Perimeter= 2(2.5 + 8feet ) + 2( 6n - 2.5 feet)

Perimeter = 5 + 16feet + 12n - 5feet

Perimeter = 5 + 12n + 11 feet

Using Length = 2.5n+ 8 feet,

Perimeter of a rectangle is calculated as 2( l+ b)

Given that width=6n - 2.5 feet

length =2.5n+ 8 feet

Perimeter =2( l+ b)= 2L + 2B

Perimeter= 2(2.5n + 8feet ) + 2( 6n - 2.5 feet)

Perimeter = 5n + 16feet + 12n - 5feet

Perimeter = 5n + 12n + 11 feet

Perimeter = 17n+ 11 feet

6 0

3 years ago

Nadia says the hypotenuse of the right triangle has a length of 73 because the Pythagorean theorem states that (28+45)squared eq

Setler79 [48]

Answer: Her solution is incorrect. The hypotenuse is 53 units

Step-by-step explanation: The error occurred when she quoted the Pythagorean theorem. She added up both sides and squared them and made the answer equal to the square of the hypotenuse. She was supposed to have squared them first, before adding up.

The Pythagorean (or Pythagoras) theorem states that the sum of the squares of two sides of a right angled triangle equals the square of the hypotenuse of the triangle. That is, in triangle ABC, if the hypotenuse is given as line AC, the Pythagoras theorem states that

AC^2 = AB^2 + BC^2

Where AC is the hypotenuse and AB and BC are the other two sides.

In Nadia’s solution, if the hypotenuse is given as 73, and the other two sides are 28 and 45, then the Pythagorean theorem properly expressed would be as follows;

73^2 = 28^2 + 45^2

5329 = 784 + 2025

5329 ≠ 2809

As we have determined, writing out the expression as

73^2 = (28 + 45)^2 is very incorrect as this is not the Pythagorean theorem and of course, the triangle cannot have 73 as its hypotenuse as we have determined by properly writing out the Pythagorean theorem.

The correct solution is as follows;

AC^2 = AB^2 + BC^2

AC^2 = 28^2 + 45^2

AC^2 = 784 + 2025

AC^2 = 2809

Add the square root sign to both sides of the equation

AC = 53

Therefore, the hypotenuse is 53 units

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3 years ago

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Studentka2010 [4]

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Step-by-step explanation

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3 years ago

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Alex_Xolod [135]

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3 years ago

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A circle has the equation x^2−8y−6x+y^2=4.

mylen [45]

Hello here is a solution :
x²-8y-6x+y²=4....(1)
A)
x²-6x = x²-2(3)x+9-9
= x²-2(3)x+3²-9
x²-6x =(x-3)² -9
B)
y²-8y = y²-2(4)y +4²-16
y²-8y = (y-4)²-16
C)
in (1) :

(x-3)² -9 +(y-4)²-16 = 4
(x-3)² +(y-4)² = 29 ...is the standard form of the equation

 Select answer 1 :
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3 years ago