Prism Volume answer from computer software.

1 answer:

6 0

I still have absolutely no idea how it got that answer. Just move on and accept that the answer is still wrong no matter what

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What else would need to be congruent to show that A ABC= AXYZ by ASA?

fredd [130]

Answer:

D. AC ≅ XZ

Step-by-step explanation:

To prove that two triangles are congruent by the Angle-Side-Angle theorem, both triangles must have two corresponding angles that are congruent to each other in each triangle, and also a corresponding included side in each triangle that are congruent.

Thus, we are given that,

<X ≅ <A and <Z ≅ <C, therefore, what is needed is a corresponding included angle in each triangle that are congruent to each other, which are,

AC and XZ

Therefore, what is needed is:

AC ≅ XZ

7 0

3 years ago

Easy! please help! <br><br> 17% is equivalent to? A. 17/100, B. 17 to 100 C. 17:100

nika2105 [10]

The answer is a obviously

3 0

3 years ago

Read 2 more answers

Barbara found that six of the 24 students in her class on a cell phone what is the ratio of students that only sell phone to stu

4vir4ik [10]

Answer:

6:24 or 1:4

Step-by-step explanation:

If you don't have to simplify, then the answer would be 6:24, but if you do, then the answer would be 1:4.

7 0

3 years ago

The midpoint of AB is at (3,7) and A is at (0,-5). Where is B located?

olga nikolaevna [1]

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ \square }}\quad ,&{{ \square }})\quad 
% (c,d)
&({{ \square }}\quad ,&{{ \square }})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)\qquad thus
\\
----------------------------\\$ $\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
A&({{ 0}}\quad ,&{{ -5}})\quad 
% (c,d)
B&({{ \square }}\quad ,&{{ \square }})
\end{array}\qquad
% coordinates of midpoint 
(3,7)\impliedby midpoint\qquad thus
\\ \quad \\
\left(\cfrac{{{ x_2 }} + {{ 0}}}{2}=3\quad ,\quad \cfrac{{{ y_2 }} + {{( -5)}}}{2}=7 \right)\to 
\begin{cases}
\cfrac{{{ x_2 }} + {{ 0}}}{2}=3
\\ \quad \\
\cfrac{{{ y_2 }} + {{ -5}}}{2}=7
\end{cases}
\\ \quad \\
solve\ for\ x_2\ and\ y_2$

3 0

3 years ago

Express as a percentage<br>25

motikmotik

Answer:

25000%

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers