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3 years ago

Need helps !!!!!!!!!!

Mathematics

2 answers:

Ilya [14]3 years ago

7 0

Its A hope this helped 100% correct

Leno4ka [110]3 years ago

5 0

The answer is A. 16.9 divided by 1.3 is 13.

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What is the domain of f

AnnZ [28]

It’ll be C all the numbers in between -7 and 7

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3 years ago

Can anyone please help me to find the area of this please

valentinak56 [21]

9514 1404 393

Answer:

√35 +3√7 -6 . . . square units

Step-by-step explanation:

The area can be figured a number of ways. The figure can be divided into parts, and the areas of those parts added.

Or, the area of the enclosing rectangle can be found, and the rectangle at upper right that is not shaded can be subtracted from that. We choose the latter.

The overall width is the sum of the given partial widths:

width = (√7 -2) + (2) = √7

Then the area of the bounding rectangle is ...

A = LW = (√5 +3)(√7) = √35 +3√7

The area of the upper right empty-space is ...

A = LW = (3)(2) = 6

Then The area of the shaded figure is ...

√35 +3√7 -6

5 0

2 years ago

HELP ASAP

Andrei [34K]

Answer:

$radius = \sqrt{13}$ or $radius = 3.61$

Step-by-step explanation:

Given

Points:

A(-3,2) and B(-2,3)

Required

Determine the radius of the circle

First, we have to determine the center of the circle;

Since the circle has its center on the x axis; the coordinates of the center is;

$Center = (x,0)$

Next is to determine the value of x through the formula of radius;

$radius = \sqrt{(x_1 - x)^2 + (y_1 - y)^2} = \sqrt{(x_2 - x)^2 + (y_2 - y)^2}$

Considering the given points

$A(x_1,y_1) = A(-3,2)$

$B(x_2,y_2) = B(-2,3)$

$Center(x,y) =Center (x,0)$

Substitute values for $x,y,x_1,y_1,x_2,y_2$ in the above formula

We have:

$\sqrt{(-3 - x)^2 + (2 - 0)^2} = \sqrt{(-2 - x)^2 + (3 - 0)^2}$

Evaluate the brackets

$\sqrt{(-(3 + x))^2 + 2^2} = \sqrt{(-(2 + x))^2 + 3 ^2}$

$\sqrt{(-(3 + x))^2 + 4} = \sqrt{(-(2 + x))^2 + 9}$

Eva;uate all squares

$\sqrt{(-(3 + x))(-(3 + x)) + 4} = \sqrt{(-(2 + x))(-(2 + x)) + 9}$

$\sqrt{(3 + x)(3 + x) + 4} = \sqrt{(2 + x)(2 + x) + 9}$

Take square of both sides

$(3 + x)(3 + x) + 4 = (2 + x)(2 + x) + 9$

Evaluate the brackets

$3(3 + x) +x(3 + x) + 4 = 2(2 + x) +x(2 + x) + 9$

$9 + 3x +3x + x^2 + 4 = 4 + 2x +2x + x^2 + 9$

$9 + 6x + x^2 + 4 = 4 + 4x + x^2 + 9$

Collect Like Terms

$6x -4x + x^2 -x^2 = 4 -4 + 9 - 9$

$2x = 0$

Divide both sides by 2

$x = 0$

This implies the the center of the circle is

$Center = (x,0)$

Substitute 0 for x

$Center = (0,0)$

Substitute 0 for x and y in any of the radius formula

$radius = \sqrt{(x_1 - 0)^2 + (y_1 - 0)^2}$

$radius = \sqrt{(x_1)^2 + (y_1)^2}$

Considering that we used x1 and y1;

In this case we have that; $A(x_1,y_1) = A(-3,2)$

Substitute -3 for x1 and 2 for y1

$radius = \sqrt{(-3)^2 + (2)^2}$

$radius = \sqrt{13}$

$radius = 3.61$ ---<em>Approximated</em>

7 0

3 years ago

Please help me !!! ASAP What can be concluded from the scatter plot

KatRina [158]

Answer:

The answer is c

6 0

3 years ago

99 Over 25 as a terminating decimal.

ahrayia [7]

I believe the answer would be 3.96 simplified

4 0

2 years ago