Answer:
we know that
the equation of the circle is of the form
(x-h)^2+(y-k)^2=r^2
where
(h,k) is the center of the circle
r is the radius of the circle
in this problem we have
(x+5)^2+(y-k)^2=r^2
so
the center is the point (-5,3)
the radius is 4 units
therefore
the answer is
The radius of the circle is equal to 4 units
5. area 0.75*2*0.75*2=2.25 m²
scale 1 in.=2 m so
Sin51=y/12
y=12sin51 units
y≈9.33 units (to nearest hundredth of a unit)
...
tanα=12/5
α=arctan2.4°
α≈67.38° (to nearest hundredth of a degree)
...
tan13=x/24
x=24tan13 units
x≈5.54 units (to nearest hundredth of a unit)
...
sin20=10/x
x=10/sin20 units
x≈29.24 units (to nearest hundredth of a unit)
Answer:
f your number is x, then the difference between that number and 8 would be x-8. Twice that is 2(x-8)
Three times the sum of the number and 3 would be 3(x+3). So, you get the equation:
2(x-8)=3(x+3)
2x-16=3x+9
x=-25
The weight of the object is only dependent on the strength of gravity on that particular object.
