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vladimir2022 [97]
3 years ago
15

26 yards at $2 per foot

Mathematics
2 answers:
muminat3 years ago
4 0
If you are looking for the cost for the 26 yards, you would first multiple 26 by 3 (being there is 3 feet per yard).

This would give you 78, which you would then multiply by 2 to get the cost. This would give you an answer of $156.

I hope this helps!!
ipn [44]3 years ago
3 0
234 US dollars is your answer
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Ok so this isn't actual homework but I need help calculating this.
jeka57 [31]
Ok so there is 60 minutes in an hour and you have 107 minutes so
107-60 = 47 ( 60 has become an hour)

So we are left with 47 minutes, so add the hour to 7:45 which will make it 8:45 pm
Then add 15 to make it 9:00 pm ( 47 - 15 = 32)

And so then add 32 minutes to 9:00 pm 

Answer is 9:32 p.m.
7 0
3 years ago
11. Tyler loves buying new sneakers. Normally they cost $80.00. Today
Minchanka [31]

Answer:

60

Step-by-step explanation:

4 0
2 years ago
Help with algebra 2 i dont know how to do this
EleoNora [17]

Answer:

I cannot see the question clearly. But I know how to do .

4 0
2 years ago
What is the common ratio of the sequence below?<br> 2 1 1 1<br> 3' 6'24' 96
anzhelika [568]

Answer:

4

Step-by-step explanation:

8 0
2 years ago
At a movie theater, admission tickets cost $10 for adults and $8 for children. On Saturday, Anne Teak collected a total of $1276
kow [346]

Answer:

Part a) variable x (the number of adult tickets sold) and variable y (the number of child tickets sold)

Part b) 10x+8y=1,276

Part c) The number of adult tickets sold was 86

Step-by-step explanation:

Part a) Name a variable for the number of adult tickets sold and name a variable for the number of child tickets sold

Let

x -----> the number of adult tickets sold

y -----> the number of child tickets sold

Part b) Write an equation in two variables to model the problem

we know that

10x+8y=1,276 -----> equation A

y=52  -----> equation B

substitute equation B in equation A and solve for x

10x+8(52)=1,276

10x+416=1,276

Part c) Using your equation in Part B, solve the problem and answer the question "how many adult tickets did Anne sell?" i

we have

10x+416=1,276

Solve for x

Subtract 416 both sides

10x=1,276-416

10x=860

x=86

therefore

The number of adult tickets sold was 86

7 0
3 years ago
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