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Nastasia [14]
2 years ago
13

False rational statement?

Mathematics
2 answers:
mars1129 [50]2 years ago
8 0
Every rational number is also an integer
Troyanec [42]2 years ago
3 0

Answer:

D. Every integer is also a rational number

Step-by-step explanation:

Every integer is also a rational number would be FALSE about a rational statement.

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WHAT IS? <br> -5(2x+14) = -2(x +63)
Rus_ich [418]
Pretty sure x=-24.5 did the math. Check my answer before you submit anything
3 0
3 years ago
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Find the value of x.
hichkok12 [17]
<h3>Angles sum up to:</h3><h3>( n - 2 ) × 180 = ( 5 - 2 ) × 180 = 3 × 180 = 540</h3>

x + 4x + 4x + 135 + 135 = 540

9x + 270 = 540

9x = 540 - 270 \\ 9x = 270

x =  \frac{270}{9}  = 30

8 0
1 year ago
Simplify 2^9/2^6<br><br> A. 2^15<br><br> B. 4^3<br><br> C. 4^-3<br><br> D. 2^3
nirvana33 [79]

Answer:

B

Step-by-step explanation:

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3 years ago
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vodomira [7]

Step-by-step explanation:

\sqrt{ x^{2}-10x+25}+25+12\sqrt{x} =15\sqrt{x} \\  \\  \therefore \: \sqrt{ x^{2}-10x+ {5}^{2} }+25 =15\sqrt{x} - 12\sqrt{x}\\  \\  \therefore \: \sqrt{( x - 5)^{2}}+25 =3\sqrt{x}  \\  \\ \therefore \:  x - 5+ 25 = 3 \sqrt{x}  \\  \\ \therefore \: x + 20 = 3 \sqrt{x}  \\  \\ squaring \: both \: sides \\ (x + 20)^{2}  = ( {3 \sqrt{x} })^{2}  \\ \therefore \:  {x}^{2}  + 40x + 400 = 9x \\ \therefore \:  {x}^{2}  + 40x + 400  - 9x = 0 \\  \therefore \:  {x}^{2}  + 31x + 400  = 0 \\

8 0
3 years ago
For F(x)=2x+1 and G(x)=c^2-7 find (FxG)(x)
Ludmilka [50]

The value of F(G(x)) is 2x^2 - 13

<h3>How to solve the composite functions?</h3>

The functions are given as:

F(x)=2x+1

G(x)=x^2-7

To find (FxG)(x), we make use of

(FxG)(x) = F(G(x))

So, we have:

F(G(x))=2G(x)+1

Substitute G(x)=x^2-7

F(G(x))=2(x^2-7)+1

Expand

F(G(x))=2x^2 - 14 + 1

Evaluate the like terms

F(G(x))=2x^2 - 13

Hence, the value of F(G(x)) is 2x^2 - 13

Read more about composite functions at:

brainly.com/question/20379727

#SPJ1

4 0
1 year ago
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