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Inga [223]
3 years ago
13

Ommy Teacher wants to analyze the weights of the students at his school. He knows the weight of the students is normally distrib

uted so he can use the standard normal distribution. He measures the weight of 100 randomly selected students in the school. He finds the mean is 80 pounds and the standard deviation is 8 pounds.
Out of 100 students, how many should weigh between 64 and 96 pounds?
Mathematics
1 answer:
marysya [2.9K]3 years ago
7 0
We first determine the z-scores for the given x-values of 64 and 96.
For x = 64: z = (64 - 80) / 8 = -2
For x = 96: z = (96 - 80) / 8 = 2
Therefore we find the probability that -2 < z < 2, which is around 0.95. Therefore, out of 100 students, approximately 100(0.95) = 95 students will weigh between 64 and 96 pounds.
You might be interested in
It is known that the life of a particular auto transmission follows a normal distribution with mean 72,000 miles and standard de
scoray [572]

Answer:

a) P(X

P(z

b) P(X>65000)=P(\frac{X-\mu}{\sigma}>\frac{65000-\mu}{\sigma})=P(Z>\frac{65000-72000}{12000})=P(z>-0.583)

P(z>-0.583)=1-P(Z

c) P(X>100000)=P(\frac{X-\mu}{\sigma}>\frac{100000-\mu}{\sigma})=P(Z>\frac{100000-72000}{12000})=P(z>2.33)

P(z>2.33)=1-P(Z

Sicne this probability just represent 1% of the data we can consider this value as unusual.

d) z=1.28

And if we solve for a we got

a=72000 +1.28*12000=87360

So the value of height that separates the bottom 90% of data from the top 10% is 87360.  

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the life of a particular auto transmission of a population, and for this case we know the distribution for X is given by:

X \sim N(72000,12000)  

Where \mu=72000 and \sigma=12000

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using excel or the normal standard table and we got:

P(z

Part b

P(X>65000)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>65000)=P(\frac{X-\mu}{\sigma}>\frac{65000-\mu}{\sigma})=P(Z>\frac{65000-72000}{12000})=P(z>-0.583)

And we can find this probability using the complement rule and excel or the normal standard table and we got:

P(z>-0.583)=1-P(Z

Part c

P(X>100000)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>100000)=P(\frac{X-\mu}{\sigma}>\frac{100000-\mu}{\sigma})=P(Z>\frac{100000-72000}{12000})=P(z>2.33)

And we can find this probability using the complement rule and excel or the normal standard table and we got:

P(z>2.33)=1-P(Z

Sicne this probability just represent 1% of the data we can consider this value as unusual.

Part d

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.1   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.9 of the area on the left and 0.1 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.9 and P(z>1.28)=0.1

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.28

And if we solve for a we got

a=72000 +1.28*12000=87360

So the value of height that separates the bottom 90% of data from the top 10% is 87360.  

5 0
3 years ago
Expand the following 5(2x-4)
Yuliya22 [10]

Answer:

x= 2

Step-by-step explanation:

5*2= 10 then add the x at the end

5*4=20

then you divide both sides by 10

(10x/10)- (20/10)

x= 2

or if your rewriting it then:

(5*2x)- (5*4)=?

Hope this helped :D

8 0
3 years ago
What is the solution to the system of equations graphed below
madreJ [45]

\underline{+\left\{\begin{array}{ccc}y=-x-1\\y=x+1\end{array}\right}\ \ \ \ |\text{add both sides}\\\\.\ \ \ \ \ 2y=0\ \ \ |:2\\.\ \ \ \ \ y=0\\\\\text{substitute the value of y to the second equation}\\\\0=x+1\ \ \ \ |-1\\x=-1\\\\Answer:\ A.\ (-1,\ 0)

8 0
3 years ago
I am working on a test review. How can I write -1 &lt;= 2x+7 &lt;21 as two inequality statements? How do I join them with and/or
Tanya [424]

Answer:

( - 1 > 2x + 7)(2x + 7 < 21)

Not sure about the and/or statement

6 0
3 years ago
Which is greater .13 or .3
Ray Of Light [21]

Answer:

.3 is greater.

Step-by-step explanation:

.13

.3 or .30

These are the same, and obviously .30 is larger than .13.

4 0
3 years ago
Read 2 more answers
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