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creativ13 [48]
3 years ago
6

Look at the attachment below! Thanks

Mathematics
1 answer:
Nataly_w [17]3 years ago
6 0
The first one is D. I not really sure about the last one
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What is the first step in solving 2x=y X+y=30
Vanyuwa [196]

Answer: x = 10 y=20

Step-by-step explanation:

You can answer this question by plugging in each equation:

2x=y, x+y=30. Let us plug y as 2x in the second equation x+y=30

x+2x= 30

3x= 30

x=10

After we found x we can then find y by plugging the 10 for x.

2(10) = y

y =20

or you could plug in the other equation

10+y=30

subtract 10 from 30 and we get 20

to double check we can plug in both numbers

2(10) = 20 which is correct

and 10 + 20 = 30 which is correct

8 0
3 years ago
If 75% of the students in Toby's grade voted, how many students are in Toby's grade?
kupik [55]

Answer:

HOW SHOULD WE KNOW WE DONT HAVE ANY INFORMATION EXCEPT 75% AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA

Step-by-step explanation:

3 0
3 years ago
What number do u divide with 11 to get the answer 17
Reika [66]
17x11=187                                              need more character there done
6 0
3 years ago
Read 2 more answers
Which equation represents the inverse
STatiana [176]

I'd say A, since there, all the operations are the opposite from the original function.

Hope it helped,

BioTeacher101

4 0
3 years ago
Find the expression that represents the length of the hypotenuse of a right triangle whose legs measure m^2-n^2 and 2mn
My name is Ann [436]
\bf c^2=a^2+b^2\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
------\\
a=m^2-n^2\\
b=2mn
\end{cases}\\\\\\ c^2=(m^2-n^2)^2+(\underline{2mn})^2
\\\\\\
c^2=m^4-2m^2n^2+n^4+\underline{2^2m^2n^2}
\\\\\\
c^2=m^4-2m^2n^2+n^4+{4m^2n^2}
\\\\\\
c^2=m^4+2m^2n^2+n^4\impliedby \textit{perfect square trinomial}
\\\\\\
c^2=(m^2+n^2)^2\implies c=\sqrt{(m^2+n^2)^2}\implies c=m^2+n^2
7 0
4 years ago
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