Why not draw the graph of y=|x|? It has a v-shape, and the vertex is at (0,0).
The graph of f(x) = |x| - 3 looks exactly the same, EXCEPT that the whole graph of |x| is shifted 3 units downward. The smallest value that y can have is therefore -3.
Can you now figure out the range of f(x)?
Any number that is less than 2 will work. It is impossible to find the square root of a negative number (you can only get imaginary number) since anything square is a positive number.
PS. If you are confused by the answer, just ask me.
Answer:
-8-8-8
Step-by-step explanation:
Answer:
C. 1
Step-by-step explanation:
Looking to the Venn's diagram, we can realize that g(1) = 0
If g(1) = 0, you just need to put 0 in place of x in f(x), so we have:
f(0) = 3√0 + 1
f(0) = 3•0 + 1
f(0) = 1
Can you take a better picture
