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3 years ago

How to figure how many hundreds there are in 150,000

2 answers:

7 0

Divide 150,000 by 100 and that quotient is the number of hundreds in 150,000.

150,000 / 100 = 1500

There are 1,500 hundreds in 150,000

Mumz [18]3 years ago

3 0

I think the answer is 1500 b/c if you divide 150000 divided by 100 that equals 1500

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Math<br> Please help me

erik [133]

Answer:

Input Output

-3 -9

2 6

1 3

0 0

5 15

-1 -3

7 21

3 9

10 30

-4 16

1/2 1.5

Step-by-step explanation: Just multiply everything by 3 I think, please tell me if I am wrong

6 0

2 years ago

Hell please and thank you !!!!

Wittaler [7]

Answer:

2.7

Step-by-step explanation:

x^2=5.8*1.3=7.54

x=V7.54=2.7

4 0

3 years ago

Read 2 more answers

A scuba diver is 3.8 meters below the surface of the water. He is descending at a rate of 0.5 meters per minute.

Andreyy89

-3.8 - 0.5m <== ur expression

the variable (m) represents number of minutes

5 0

3 years ago

Read 2 more answers

Does anyone know how to do these maths question???

Dmitry_Shevchenko [17]

Answer:

Part 1) $f(g(x))=3(x^2)+2$

Part 2) $g(f(5))=289$

Step-by-step explanation:

we know that

A composite function is a function that depends on another function. A composite function is created when one function is substituted into another function

we have

$f(x)=3x+2$

$g(x)=x^{2}$

Part 1) Determine f(g(x))

To find f(g(x)) substitute the function g(x) as the variable in function f(x)

$f(g(x))=3(x^2)+2$

Part 2) Determine g(f(x))

To find g(f(x)) substitute the function f(x) as the variable in function g(x)

$g(f(x))=(3x+2)^2$

For x=5

$g(f(5))=(3(5)+2)^2$

$g(f(5))=289$

3 0

3 years ago

Two slits are illuminated by a 348 nm light. The angle between the zeroth-order bright band at the center of the screen and the

Andre45 [30]

Answer:0.369 m

Step-by-step explanation:

Given

Distance between slit and screen is $D=154 cm$

Wavelength $\lambda =348 nm$

Angle between zeroth order bright fringe and Fourth-order bright fringe is $\theta =13.5^{\circ}$

let distance between the slits be d

Distance of n th bright fringe From central Fringe is given by

$y_n=\frac{nD\lambda }{d}$

Also $\tan \theta =\frac{y_4}{D}$

$y_4=\tan (13.5)\cdot 1.54$

$y_4=0.24\times 1.54$

$y_4=0.369 m$

5 0

3 years ago