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4 years ago

Simplify please!!!!!!!!!!!!!

Mathematics

1 answer:

Licemer1 [7]4 years ago

4 0

Follow order of operations and the answer is 32

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6.) Alan, Becky, Jesus, and Mariah are four students in the chess club. If two of these students will be selected to represent t

Artist 52 [7]

Let's begin by listing out the information given to us:

There are four students: n = 4

Number of students to be selected: r = 2

To calculate the combination of 2 students to be chosen, we use:

$\begin{gathered} ^4C_2=\frac{n!}{(n-r)!}=\frac{4!}{(4-2)!}=\frac{4!}{2!} \\ ^4C_2=\frac{4\cdot3\cdot2\cdot1}{2\cdot1}=\frac{4\cdot3}{1}=12 \\ ^4C_2=12 \end{gathered}$

Therefore, there 12 possible combinations from these

3 0

2 years ago

Which of the following is true for the relation f(x) = 2x2 + 1?

guajiro [1.7K]

Neither the equation nor its inverse is a function

8 0

3 years ago

Read 2 more answers

Help me, I will mark brainliest !

Anna35 [415]

Answer:

12 pencils in each

Step-by-step explanation:

brainliest pls

I answered first

5 0

3 years ago

Read 2 more answers

Which lines are perpendicular to the line y - 1 = 1(x+2)? Check all that apply.

Drupady [299]

Answer:

The general equation of the lines that are perpendicular is:

$y=-x+b$

b can by any number.

Step-by-step explanation:

The equation of a line is given by:

$y=mx+a$

where m is the slope and b is the intercept

The equation of a perpendicular line to the previuos one is:

$y=- \frac{1}{m} x+b$

That means that the slope of a perpendicular line is inverse and sign opposite to the other line.

Hence, the equation given is:

$y - 1 = 1(x+2) \\ y=x+2+1 \\ y=x+3$

m would be:

m=1

So the perpendicular slope would be:

$- \frac{1}{m}=- \frac{1}{1} =-1$

The general equation of the lines that are perpendicular to y=x+3 is:

$y=-x+b$

b can be any number

In attached picture:

y=x+3 is the red line

y=-x+b is the blue line

7 0

3 years ago

On a coordinate plane, parallelogram A B C D has points (3, 6), (6, 5), (5, 1), and (2, 2).

Vlad1618 [11]

Answer:

Area of parallelogram ABCD=13.05=13 Sq.Units

Step-by-step explanation:

Given;

A(3,6) B(6,5) C(5,1) and D(2,2)

are points for parallelogram

To Find:

Area of Parallelogram ABCD

Solution:

By using distance formula we can calculate for each length of parallelogram

But by property of parallelogram

Opposite side are parallel and equal in length

So AB|| DC i.e AB=DC

And AC|| BD i.e BD=AC

Hence I.e Dist(AB)=Dist(DC)

Now construct the ABCD parallelogram ,on graph so as to find angle made by parallelogram with plane .

(Refer the attachment)

Now

Distance of AD=Sqrt[(2-3)^2+(2-6)^2]

=Sqrt[1+16]

=4.123

Similarly for AB=Sqrt[(6-3)^2+(5-6)^2]

=Sqrt[9+1]

=3.16

ABOVE VALUES ARE SAME AS GRAPH (REFER THE ATTACHMENT)

Now ,angle made by parallelogram with plane and it is 90 degree i.e the

Now Area of parallelogram(ABCD)=a*b*sinФ

here a=4.123 units and b=3.16 units and Ф=90

Area of parallelogram=3.167*4.123*sin90

=3.167*4.123

=13.05 sq. units

3 0

3 years ago

Read 2 more answers