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GrogVix [38]
3 years ago
8

The first computer (the eniac was how big

Computers and Technology
1 answer:
sattari [20]3 years ago
3 0
The first computer is the Eniac which was 50 tons!
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Suppose a process in Host C has a UDP socket with port number 6789. Suppose both Host A and Host B each send a UDP segment to Ho
Ann [662]

Answer:

Yes, both of these segments (A and B) will be directed to the same socket at Host C .

Explanation:

Suppose both Host A and Host B each send a UDP segment to Host C with destination port number 6789, surely , both of these segments will be directed to the same socket at Host C .

Reason being that,  the operating system will provide the process with the IP details to distinguish between the individual segments arriving at host C- for each of the segments (A and B) recieved at Host C.

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The Texas Department of Education has offices throughout the state covering more than 268,000 square miles. State documents are
notka56 [123]

Answer: WAN

Explanation:

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2 years ago
Why should you stay out of the open space to the right of a semi tractor trailer?
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The right side to a semi tractor trailer is their huge blind side, meaning the driver can't see you, and may merge lanes with you, thus crashing into you.
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Bytes are typically represented with a lowercase b and bits with an uppercase B.<br> true or false
34kurt

Answer:

False

Explanation:

Byte(B) is uppercase

bit(b) is lowercase

Good way to remember is that its takes 8 bits makes a byte. In other word, a byte is bigger than a bit so it makes sense that byte is uppercase.

7 0
3 years ago
Design a program takes as input, X, an unsorted list of numbers, and returns the sorted list of numbers in X. The program must b
Lelechka [254]

Answer:

The program in python is as follows:

def split(X):

   L = []; G = []

   for i in range(len(X)):

       if X[i]>=X[0]:

           G.append(X[i])

       else:

           L.append(X[i])

   L.sort(); G.sort()

   return L,G

X = []

n = int(input("Length of X: "))

for i in range(n):

   inp = int(input(": "))

   X.append(inp)

   

if len(X) == 0 or len(X) == 1:

   print(X)

else:

   X1,X2=split(X)

   newList = sorted(X1 + X2)

   print(newList)

Explanation:

The following represents the split function in the previous problem

def split(X):

This initializes L and G to empty lists

   L = []; G = []

This iterates through X

   for i in range(len(X)):

All elements of X greater than 0 equal to the first element are appended to G

      <em> if X[i]>=X[0]:</em>

<em>            G.append(X[i])</em>

Others are appended to L

<em>        else:</em>

<em>            L.append(X[i])</em>

This sorts L and G

   L.sort(); G.sort()

This returns sorted lists L and G

   return L,G

The main function begins here

This initializes X

X = []

This gets the length of list X

n = int(input("Length of X: "))

This gets input for list X

<em>for i in range(n):</em>

<em>    inp = int(input(": "))</em>

<em>    X.append(inp)</em>

This prints X is X is empty of has 1 element

<em>if len(X) == 0 or len(X) == 1:</em>

<em>    print(X)</em>

If otherwise

else:

This calls the split function to split X into 2

   X1,X2=split(X)

This merges the two lists returned (sorted)

   newList = sorted(X1 + X2)

This prints the new list

   print(newList)

7 0
2 years ago
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