Since the congruent operator is ≅ and since AD is congruent to BD, I'm going to assume that you want to prove that AD is congruent to BD.
1. DE is equal to CD by definition since D is the midpoint of CE.
2. AE is equal to BC since opposite sides of a rectangle are equal to each other.
3. Angle AEC is equal to Angle BCE since all angles in a rectangle are right angles and all right angles are equal to each other.
4. Triangles ADE and BDC are congruent to each other because we have SAS congruence for both triangles.
5. AD is congruent to BC since they're corresponding sides of congruent triangles.
Answer:
This should be parallel.
Step-by-step explanation:
Two lines are said to be parallel only if their slope matches. They are said to be perpendicular only if the slopes are negative reciprocals.
Here, you should put both equations in slope intercept form which is y=mx+b. The letter "M" represents the slope of both equations.
2y-6=3x+4 turns into 2y=3x+10 after adding 6 and into y=3/2x+5 after dividing the equation by 2. The slope for this equation is 3/2.
8y=12x+8 must be divided by 8 to be in slope intercept form. This equation becomes y=3/2x+1. Here the slope is also 3/2.
The slopes for each equation match making these lines parallel.
So base on your question that ask to provide and end point of the four statement you give:
1.Endpoint(-1,9), midpoint:(-9,-10) - (-17, -29)
2.Endpoint(2,5), midpoint(5,1) - (4,5)
3.Endpoint(9,-10), midpoint(4,8) - i cant determine sorry
4.Find the point that is one-fourth of the way from (2,4) to (10,8) - also i cant.
Step-by-step explanation:
Area of circle= Πr²
Πr² = 132² m
r²=132²/Π m
=5546.23m
r =√5546.23
=74.473 m
