Answer:
the answer is 12
Step-by-step explanation:
I can help, but I didn’t see a question posted. I’m not sure if you tried to post a picture or something, but I don’t see a question.
The question is incomplete. The complete question is :
Let X be a random variable with probability mass function
P(X =1) =1/2, P(X=2)=1/3, P(X=5)=1/6
(a) Find a function g such that E[g(X)]=1/3 ln(2) + 1/6 ln(5). You answer should give at least the values g(k) for all possible values of k of X, but you can also specify g on a larger set if possible.
(b) Let t be some real number. Find a function g such that E[g(X)] =1/2 e^t + 2/3 e^(2t) + 5/6 e^(5t)
Solution :
Given :
a). We know :
So,
Therefore comparing both the sides,
Also,
b).
We known that
∴
Therefore on comparing, we get
∴
I participants. If you look at the line plot, for 6, there’s nothing there, meaning no one hit 6 kind.