It is given that there are 41 males and 48 females in the small school.
So, the number of ways a male student can be chosen from 41 males is 
Likewise, the number of ways a female student can be chosen from 48 females is 
.
Thus, the total number of ways in which 2-person combinations are possible to represent the student body at the PTSAC meetings will be given by:
Step 1: Find the area of the bases (triangles)
A = 1/2 * base * height
A = 1/2 * 16 * 6
A = 48
48 + 48 = 96
Area of the triangles = 96 cm^2
Step 2: Find the area of the sides (rectangles)
A = base * height
A1 = 16 * 12
A1 = 192
A2 = 10 * 12
A2 = 120
120 + 120 = 240
240 + 192 = 432 cm^2
Step 2: Add the areas together
96 + 432
528 cm^2
Hope this helps!! :)
138.43-19.99=118.44
118.44/0.94=126.
Hope this helps :)
Answer:
The range of possible values for the third side called c is;
11 > c or c < 11
Step-by-step explanation:
Here in this question, we are concerned with giving the range of the third side of the triangle.
What we will be using to get this range is the triangle inequality theorem.
Mathematically, the sum of the length of the two sides must be greater than the length of the third side.
So let’s call the third side c
Thus, the range of values we are to work with is;
5 + 6 > c
11 > c
10 and 2 :)
i hope you have a great day :)
