The general approach to this is to write the (x, y) coordinates of the trajectory's peak in terms of the sine and cosine of the launch angle α. Then use a trig identity (sin(2α)² + cos(2α)² = 1) to eliminate the dependence on α.
You should get
t = v₀sin(α)/g
x = v₀²sin(2α)/(2g)
y = v₀²(1-cos(2α))/(4g)
Solve each of the latter two equations for the trig function, then substitute those expressions into the trig identity above. Divide by the coefficient of x² and rearrange to get the expression shown.
Answer:
D. CBA
Step-by-step explanation:
If b was the third point, then it would be C. ACB.
AB+BC=ABC or CBA
Write 12.54 as 12.54/1. Multiply both numerator and denominator by 10 for every number after the decimal point
<span>12.54 × 100/1 × 100</span><span> = </span><span>1254/100. </span>Reducing the fraction gives
<span>627/<span>50. Idk if this is actually right, but here you go. </span></span>
Answer:7+2/
Step-by-step explanation:
Answer:
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