What is 5% of $30,000

Mathematics

1 answer:

ValentinkaMS [17]4 years ago

7 0

30000= 100%
x=5%
30000/x=100/5
(30000/x)*x=(100/5)*x
30000=20*x
30000/20=x
x=1500
5%of 30000 is 1500

You might be interested in

A ball is thrown upward from the top of a building. The function below shows the height of the ball in relation to sea level, f(

Sindrei [870]

First, we differentiate the equation for the distance so to find the velocity in feet per second (ft/s).
                                f(t) = -16t² + 48t + 100
Differentiating,
                              df(t)/dt = -32t + 48
The value at t = 3 is,
                            df(t) / dt = -32(3) + 48 = -48 ft/s
The value at t = 5 is
                           df(t) / dt = -32(5) + 48 = -112 ft/s

The average of both values is -80 ft/s.

5 0

3 years ago

Assume that the random variable X is normally distributed, with mean μ = 90 and standard deviation σ = 12. Compute the probabili

madam [21]

The probability P(X < 105), assuming that the random variable X is normally distributed, with mean μ = 90 and standard deviation σ = 12 is calculated to be 0.8944.

When a random variable X is normally distributed, with the mean as μ, and standard deviation as σ, then the probability P(X < x) is calculated using the Z-score table, as the probability P(Z < z), where z is calculated using the formula, z = (x - μ)/σ.

In the question, we are asked to find the probability P(X < 105), assuming that the random variable X is normally distributed, with mean μ = 90 and standard deviation σ = 12.

We calculate as follows:

P(X < 105)

= P(Z < (105-90)/12)

= P(Z < 1.25)

Now we check the z-score table for the value of z as 1.25.

On the left column we choose the value 1.2.

On the top row, we choose the value .05.

The intersection of these, gives us the value,

P(Z < 1.25) = 0.8944.

Thus, the probability P(X < 105), assuming that the random variable X is normally distributed, with mean μ = 90 and standard deviation σ = 12 is calculated to be 0.8944.

Learn more about probability for normal distribution at

brainly.com/question/14530400

#SPJ1