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yanalaym [24]
3 years ago
14

Select the correct answer.

Mathematics
1 answer:
Mariulka [41]3 years ago
5 0
The answer would be B
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3 years ago
An object is launched directly in the air at a speed of 48 feet per second from a platform located 12 feet above the ground. The
anastassius [24]

9514 1404 393

Answer:

  48 ft

Step-by-step explanation:

For the quadratic ax^2 +bx +c, the axis of symmetry is x = -b/(2a). For the given quadratic, which defines a parabola opening downward, the axis of symmetry defines the time at which the maximum height is reached.

  t = -48/(2(-16)) = 1.5

Then the maximum height is ...

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  f(1.5) = 48

The maximum height the object will reach is 48 feet.

6 0
3 years ago
Explain how you would find the perimeter of this triangle.
Lynna [10]

Answer:

<em>15.4 </em>

Step-by-step explanation:

\frac{u}{4} = tan51.3° ⇒ u = 4tan51.3° ≈ 5

\frac{4}{v} = cos51.3° ⇒ v = \frac{4}{cos51.3} ≈ 6.4

<em>P </em>≈ 4 + 5 + 6.4 = <em>15.4</em>

4 0
2 years ago
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