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sleet_krkn [62]
3 years ago
13

The difference of a number and sixteen​

Mathematics
1 answer:
Maksim231197 [3]3 years ago
6 0

This is it if you want it written as an equation:

n - 16

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Can someone please help me?the question is in the picture. Thank you
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Answer:

B

Step-by-step explanation:

The two triangles are congruent because they have three rispective side congruent

AB and AD are both radiuses and AC is in common

so m arc BC is 78 degrees

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A package of tickets for four home game costs 180$. What proportion can you write to find what 12-game package costs if all indi
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john is a proud owner of a herd of cows 12 of them are brown and 32 are black what is the ratio of brown cows to the total numbe
Burka [1]

Answer:

12:44, or if simplified 3:11

Step-by-step explanation:

In mathematics, a ratio indicates how many times one number contains another. For example, if there are eight oranges and six lemons in a bowl of fruit, then the ratio of oranges to lemons is eight to six (that is, 8∶6, which is equivalent to the ratio 4∶3). Similarly, the ratio of lemons to oranges is 6∶8 (or 3∶4) and the ratio of oranges to the total amount of fruit is 8∶14 (or 4∶7).

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3 years ago
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Rename the fraction 1/4 using the least common denominator,12
kiruha [24]

Answer:

3/12

Step-by-step explanation:
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2 years ago
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According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are re
Anna35 [415]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

P(brown) = 12% = 0.12

P(Yellow) = 15% = 0.15

P(Red) = 12% = 0.12

P(blue) = 23% = 0.23

P(orange) = 23% = 0.23

P(green) = 15% = 0.15

A.) Compute the probability that a randomly selected peanut M&M is not yellow.

P(not yellow) = P(Yellow)' = 1 - P(Yellow) = 1 - 0.15 = 0.85

B.) Compute the probability that a randomly selected peanut M&M is brown or red.

P(Brown) or P(Red) :

0.12 + 0.12 = 0.24

C.) Compute the probability that three randomly selected peanut M&M’s are all brown.

P(brown) * P(brown) * P(brown)

0.12 * 0.12 * 0.12 =0.001728

D.) If you randomly select three peanut M&M’s, compute that probability that none of them are blue.

P(3 blue)' = 1 - P(3 blue)

P(3 blue) = 0.23 * 0.23 * 0.23 = 0.012167

1 - P(3 blue) = 1 - 0.012167 = 0.987833

If you randomly select three peanut M&M’s, compute that probability that at least one of them is blue.

P(1 blue) + p(2 blue) + p(3 blue)

(0.23) + (0.23*0.23) + (0.23*0.23*0.23)

0.23 + 0.0529 + 0.012167

= 0.295067

5 0
3 years ago
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