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maria [59]
2 years ago
5

tanner collected 360 cans and bottles, this was 40% of what Reggie collected, how many cans and bottles did Reggie collect

Mathematics
2 answers:
Kay [80]2 years ago
5 0
360x.6+360=576
I got .6 because 40% would be .4 and 40+60=100
So Riggie collected 576 cans and bottles
s2008m [1.1K]2 years ago
3 0


Tanner = 40% * Reggie;

Reggie = Tanner : 40%;

Reggie = 360 : 40/100 = 360 * 100/40 = 900 bottles

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142.2 meters.  

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\text{Total surface area of cuboid}=2(lb+bh+hl), where,

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\text{Total surface area of box}=2(2520+432+840)

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Therefore, the total surface area of box will be 7584 square cm.  

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}

80\text{ cm}\times\text{ Length of canvass}=150\times 7584\text{cm}^2

\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=\frac{1137600\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=14220\text{ cm}

Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100}\times\frac{m}{cm}

\text{ Length of canvass}=142.20\text{ m}

Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.

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