Answer:
b=0
c=0
lol=list()
while True:
salary=input("Enter your salary: ")
if salary=="e" or salary=="E":
print("Thankyou!!")
break
else:
a=int(salary)
if a>=300000 and a<=400000:
c=c+1
if a<0 or a>400000:
print("Your salary is either too small or too big ")
if a>0 and a<=400000:
a=a-(25/100*a)-(5/100*a)-(2/100*a)
lol.append(a)
b=b+1
if a>=300000:
c=c+1
print(lol)
print("The number of salaries entered is: "+ str(b))
print("The number of salaries that exceeded 300000 is: "+str(c))
<span>You should do it if C. it will take less than two minutes to complete </span>
I think it is d but not exactly sure
There is only one programming language that is closest to a human language and is the most easy to learn other than HTML or CSS.
That language would be AppleScript. for both its simplicity and power, it has become an ideal language for basic Apple programmers to learn.
Answer:
Bird baths, open containers, gutters, drainage systems