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ZanzabumX [31]
3 years ago
14

What formula is required

Mathematics
1 answer:
Yuliya22 [10]3 years ago
8 0
The formula required is tangent
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ki77a [65]
<span>x = -2.375 Hopefully that helps :)</span>
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2 years ago
Ben drives 405 miles on 15 gallons. How many miles does Ben drive on one gallon? HELP ASAP
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Iauida girgel 39 for mayos
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3 years ago
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5-1+2x(4x4-12)x8<br><br> explain
Romashka [77]

First, do what's in the paranthesis:

(4*4-12)

Multiplication first:

16-12

Then subtract:

4

We get:

5-1+2*4*8

Multiply:

2*4

8

Multiply, again:

8*8

64

We get:

5-1+64

Subtract:

5-1

4

Add:

4+64

Answer: 68

5 0
3 years ago
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Samuel and Jason sell cans to a recycling center that pays $0.40 per pound of cans. The table shows the number of pounds of cans
Goryan [66]

Answer:

I believe 2 batteries

Step-by-step explanation:

17.4 pounds from monday + 13.3 from Tuesday= 30.7 pounds.

30.7 pounds times $0.40 is $12.28

12.28/5.5 is 2.327272727...

You cant buy .3 of a batter so the answer should be 2

6 0
3 years ago
-6n5x^3÷18nx^7<br>12m^8y^6÷-9my^4​
umka2103 [35]

Answer:

(-n^4 - 4 m^7 x^4 y^2)/(3 x^4)

Step-by-step explanation:

Simplify the following:

(-6 n^5 x^3)/(18 n x^7) + (12 m^8 y^6)/(-9 m y^4)

The gcd of -6 and 18 is 6, so (-6 n^5 x^3)/(18 n x^7) = ((6 (-1)) n^5 x^3)/((6×3) n x^7) = 6/6×(-n^5 x^3)/(3 n x^7) = (-n^5 x^3)/(3 n x^7):

(-1 n^5 x^3)/(3 n x^7) + (12 m^8 y^6)/(-9 m y^4)

Combine powers. (-n^5 x^3)/(3 n x^7) = (n^(5 - 1) x^(3 - 7) (-1))/3:

-(n^(5 - 1) x^(3 - 7))/3 + (12 m^8 y^6)/(-9 m y^4)

5 - 1 = 4:

-(n^4 x^(3 - 7))/3 + (12 m^8 y^6)/(-9 m y^4)

3 - 7 = -4:

-(n^4 x^(-4))/3 + (12 m^8 y^6)/(-9 m y^4)

The gcd of 12 and -9 is 3, so (12 m^8 y^6)/(-9 m y^4) = ((3×4) m^8 y^6)/((3 (-3)) m y^4) = 3/3×(4 m^8 y^6)/(-3 m y^4) = (4 m^8 y^6)/(-3 m y^4):

(4 m^8 y^6)/(-3 m y^4) - (n^4)/(3 x^4)

Combine powers. (4 m^8 y^6)/(-3 m y^4) = (4 m^(8 - 1) y^(6 - 4))/(3 (-1)):

-(n^4)/(3 x^4) + (4 m^(8 - 1) y^(6 - 4))/(-3)

8 - 1 = 7:

-(n^4)/(3 x^4) + (4 m^7 y^(6 - 4))/(-3)

6 - 4 = 2:

-(n^4)/(3 x^4) + (4 m^7 y^2)/(-3)

Multiply numerator and denominator of (4 m^7 y^2)/(-3) by -1:

-4/3 m^7 y^2 - (n^4)/(3 x^4)

Put each term in -(n^4)/(x^4×3) - (4 m^7 y^2)/3 over the common denominator 3 x^4: -(n^4)/(x^4×3) - (4 m^7 y^2)/3 = (-n^4)/(3 x^4) - (4 m^7 x^4 y^2)/(3 x^4):

-n^4/(3 x^4) - (4 m^7 x^4 y^2)/(3 x^4)

-n^4/(3 x^4) - (4 m^7 x^4 y^2)/(3 x^4) = (-n^4 - 4 m^7 x^4 y^2)/(3 x^4):

Answer: (-n^4 - 4 m^7 x^4 y^2)/(3 x^4)

5 0
2 years ago
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