What formula is required

Marie has a small copy of Rene Magritte's famous painting, The Schoolmaster. Her copy has dimensions 2 inches by 1.5 inches. The

avanturin [10]

A scale of 1:40 can be read as "one cm on the model corresponds to 40 cm in the original object". or

"one inch on the model corresponds to 40 inches
this means that the 2 inches correspond to 2 times 40, that is 80 inches and 1.5 corresponds to 1.5*40=60 inches

which means that the original painting has dimensions of 80 by 60 inches.
b) Area = 80 cm * 60 cm = 4,800 cm²
c) 80 cm * 1 inch / 2.54 cm = 31.50 inches ;
60 cm * 1 inch/2.54 cm = 23.60 inches
d) Area = 31.50 in * 23.60 in = 743.40 inches²

5 0

3 years ago

Eloise started to solve a radical equation in this way: Square root of negative 2x plus 1 − 3 = x Square root of negative 2x plu

SOVA2 [1]

Eloise made these steps well:
Square root of negative 2x plus 1 - 3 = x
Square root of negative 2x plus 1 - 3 + 3 = x + 3
The error comes in the next step:
Square root of negative 2x plus 1 = x + 3
Square root of negative 2x plus 1 -1 = x + 3 - 1
Square root of negative 2x = x + 2
the number one is inside the root, therefore they can not be subtracted.
answer
error in the step:
Square root of negative 2x = x + 2

5 0

3 years ago

Read 2 more answers

The measure of each angles

Aleks [24]

Supplementary angles is when 2 angles add up to 180 degrees.

We will name the smaller angle a and the bigger angle b.

therefore:

b - 172.6 = a

a + b = 180

Now we substitute:

a + b = 180
b - 172.6 + b = 180
2b - 172.6 = 180
2b = 352.6
b = 176.3

To find a:

a + b = 180
a + 176.3 = 180
a = 3.7

Therefore,

angle a = 3.7 degrees
angle b = 176.3 degrees.

Hope it helps and have a great day ahead

4 0

4 years ago

The radius of a cylinder water tank is 4.5 ft, and it’s height is 10 ft.what is it’s volume

Irina18 [472]

Volume of a cylinder is pi*r^2*h so we get

3.14*4.5^2*10=636.2cubic feet or ft^3

Thank you! Please rate brainliest if I helped you! Thank you so much!!!

8 0

4 years ago

Me. Ellis is a teacher who tutors after school. Of the students he tutors, 30% need help in computer science and 70% need assist

Anna11 [10]

Answer: There are 82.5% after school students who are enrolled in his classes.

Step-by-step explanation:

Let the total number of students be 100

Percentage of students who need help in computer science = 30%

So, number of students who need help in computer science = 30

Percentage of students who need help in maths = 70%

So, number of students who need assistance in maths = 70

Of the students who need help,

40% are enrolled in Mr. Ellis's class during the school day,

So, it means 60% are enrolled in his class after the school day.

Number of students who are enrolled in his class after the school day = 60

Number of students who need help in Maths is given by

$\frac{70}{100}\times 60=42$

Of the students that need help in maths, percent of students are enrolled in his class during the day = 25%

So, number of students who need help in maths and enrolled in his class after school hours

$\frac{75}{100}\times 42=31.5$

Number of students who need help in computer science and enrolled in his class after school hours

$\frac{30}{100}\times 60=18$

Therefore, there are $31.5+18=49.5$ students who joined his class after school hours,

Percentage of the after students who are enrolled in Mr. Ellis's classes is given by

$\frac{49.5}{60}\times 100=82.5\%$

Hence, there are 82.5% after school students who are enrolled in his classes.

6 0

4 years ago