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Cerrena [4.2K]
4 years ago
7

If a file is opened for reading and the file does not exist,what action is taken?

Computers and Technology
1 answer:
worty [1.4K]4 years ago
8 0

Answer:

C)An error message is issued.

Explanation:

If we try to open a file for reading when that file does not exist, we will get an error message.

For example, in Java we will encounter a FileNotFoundException as in the code below:

       try {

           FileInputStream fis = new FileInputStream("myFile.txt");

           DataInputStream dis = new DataInputStream(fis);

           BufferedReader br = new BufferedReader(new InputStreamReader(dis));

           String str = null;

           while ((str = br.readLine()) != null) {

               System.err.println(str);

           }

       } catch (FileNotFoundException e) {

           e.printStackTrace();

       }

If the file myFile.txt does not exist we can expect to see an exception stack trace corresponding to FileNotFoundException.

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What will be the value of x after the following code is executed? int x = 10; do { x *= 20; } while (x < 5); A. 10 B. 200 C.
dezoksy [38]

Answer:

Option B is the correct answer.

Explanation:

  • In the above code, the loop will execute only one time because the loop condition is false and it is the Do-While loop and the property of the Do-while loop is to execute on a single time if the loop condition is false.
  • Then the statement "x*=20;" will execute one and gives the result 200 for x variable because this statement means "x=x*20".
  • SO the 200 is the answer for the X variable which is described above and it is stated from option B. Hence it is the correct option while the other is not because--
  1. Option A states that the value is 10 but the value is 200.
  2. Option C states that this is an infinite loop but the loop is executed one time.
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3 years ago
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professor190 [17]

Here's the biology explanation:

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4 years ago
Design pseudocode for a program that will permit a user to store exactly 50 numbers in an array. Create an array big enough to h
galben [10]

Answer:

#include<stdio.h>

//declare a named constant

#define MAX 50

int main()

{

   //declare the array

   int a[MAX],i;

   //for loop to access the elements from user

   for(i=0;i<MAX;i++)

   {

      printf("\n Enter a number to a[%d]",i+1);

      scanf("%d",&a[i]);

  }

  //display the input elements

  printf("\n The array elements are :");

  for(i=0;i<=MAX;i++)

  printf(" %d ",a[i]);

}

Explanation:

PSEUDOCODE INPUTARRAY(A[MAX])

REPEAT FOR I EQUALS TO 1 TO MAX

PRINT “Enter a number to A[I]”

READ A[I]

[END OF LOOP]

REPEAT FOR I EQUALS TO 1 TO MAX

PRINT A[I]

[END OF LOOP]

RETURN

ALGORITHM

ALGORITHM PRINTARRAY(A[MAX])

REPEAT FOR I<=1 TO MAX

PRINT “Enter a number”

INPUT A[I]

[END OF LOOP]

REPEAT FOR I<=1 TO MAX

PRINT A[I]

[END OF LOOP]

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Hope this helps!

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