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ratelena [41]
3 years ago
9

8x+10-2x-2 what is the answer I need help

Mathematics
2 answers:
astra-53 [7]3 years ago
8 0
8x+10-2x-2
(8x-2x)+(10-2)
6x+8
Ira Lisetskai [31]3 years ago
5 0
Answer- 6x+ 8
Yet you can not be
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Three times one number added to five times another number is 54. The second number is two less than the first. Use a system of e
worty [1.4K]

Answer:

8 and 6

Step-by-step explanation:

If you use x for the first number, and y for the second, you get equations of 3x+5y=54 and x-2=y.

You can substitute the second equation into the first one to solve it. This gives 3x+5(x-2)=54.

The brackets can be expanded to 3x+5x-10=54. Collecting like terms makes it 8x-10=54.

Next, we add 10 to both sides. This gives 8x=64.

From there, we isolate the x by dividing both sides by 8, giving x=8.

To work out the second number, we can sub 8 for x in either equation (I'm using the second one as it's simpler).

This comes to y=8-2, therefore y=6.

**This content is simultaneous equations, which you may wish to revise. I'm always happy to help!

3 0
3 years ago
Find angle B and angle E
Natali [406]

Answer:

x = 9, Angles are 54°

Step-by-step explanation:

First, we need to find x:

7x-9 = 5x+9

+9 +9

7x = 5x+18

-5x -5x

2x = 18

x = 9

Now, we plug our x value in to find our angles.

5(9) + 9 = 54

Angle B = 54°

7(9) - 9 = 54°

Angle E = 54°

(angles are the same due to AAA property)

6 0
3 years ago
Members of a landscaping company built a retaning Wallet.
algol [13]

Answer:

Is this a question. If so I will change my answer

Step-by-step explanation:

3 0
3 years ago
I don’t understand what #5 is asking me to do! Ty
Aleksandr-060686 [28]

You have to explain how you knew to use 55 and 120, not another option.

Hope it helped! :)

4 0
3 years ago
Which shows the expression x^2-1/x^2-x in simplest form
____ [38]

Answer:

\large\boxed{\dfrac{x+1}{x}=1+\dfrac{1}{x}}

Step-by-step explanation:

\dfrac{x^2-1}{x^2-x}=(*)\\\\x^2-1=x^2-1^2\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\=(x-1)(x+1)\\\\x^2-x=(x)(x)-(x)(1)\qquad\text{use the distributive property}\\=x(x-1)\\\\(*)=\dfrac{(x-1)(x+1)}{x(x-1)}\qquad\text{cancel}\ (x-1)\\\\=\dfrac{x+1}{x}=\dfrac{x}{x}+\dfrac{1}{x}=1+\dfrac{1}{x}

4 0
3 years ago
Read 2 more answers
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